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Elodia [21]
3 years ago
8

Find the range of the function for the given domain. F(x)= 3x-8; {-2, -1, 0, 1, 2}

Mathematics
1 answer:
Serga [27]3 years ago
4 0
Subtitute x in the function with -2,-1,0,1,2 to find the range
f(x) = 3x - 8

f(-2) = 3(-2) - 8
f(-2) = -6 - 8
f(-2) = -14

f(-1) = 3(-1) - 8
f(-1) = -3 - 8
f(-1) = -11

f(0) = 3(0) - 8
f(0) = 0 - 8
f(0) = -8

f(1) = 3(1) - 8
f(1) = 3 - 8
f(1) = -5

f(2) = 3(2) - 8
f(2) = 6 - 8
f(2) = -2

The range of the function
f(x) = {-14, -11, -8, -5, -2}
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Answer:

The probability that a randomly selected automobile manufactured by the company will have a defective microprocessor is 6.2 %.

Step-by-step explanation:

Given:

The probability of getting a microprocessor from firm A is, P(A)=45\%=0.45

The probability of getting a microprocessor from firm B is, P(B)=30\%=0.30

The probability of getting a microprocessor from firm C is, P(C)=25\%=0.25

Now, let event D be having a defective microprocessor at random.

So, as per the question,

Probability of producing a defective microprocessor from firm A is, P(D/A)=6\%=0.06

Probability of producing a defective microprocessor from firm B is, P(D/B)=7\%=0.07

Probability of producing a defective microprocessor from firm C is, P(D/C)=5.5\%=0.055

Now, probability of having a defective microprocessor when selected at random is given as:

P(D)=P(A)\cdot P(D/A)+P(B)\cdot P(D/B)+P(C)\cdot P(D/C)\\P(D)=(0.45\times 0.06)+(0.30\times 0.07)+(0.25\times 0.055)\\P(D)=0.027+0.021+0.01375\\P(D)=0.06175\ or\ P(D)=0.06175\times 100\approx 6.2\%

Therefore, the probability that a randomly selected automobile manufactured by the company will have a defective microprocessor is 6.2 %.

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I believe the answer is A.

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Absolute value is how far a number is from zero.
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Step-by-step explanation:

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