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givi [52]
3 years ago
11

Which system has no solution? Check all that appy.

Mathematics
1 answer:
Ainat [17]3 years ago
7 0
The first equation has no solution



The picture shows all the work I did, the reason I took a pic is because it is a little hard to explain by text, but I hope this helped you!

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At a used dealership, let X be an independent variable representing the age in years of a motorcycle and Y be the dependent vari
GarryVolchara [31]

Answer:

a) Selling price y= a + b (age x)

b)

a= 728.025

b= -38.217

c)

Selling price y = 728.025 - 38.217 age x

d)

SSE=8280.25

Step-by-step explanation:

a)

The regression model can be written as

y=a+bx

Here y=selling price and x is age.

So, the regression model will be

Selling price y= a + b (age x)

b)

We have to find the values of "a" and "b"

b=\frac{nsumxy-(sumx)(sumy)}{nsumx^{2} -(sumx)^2}

sumx=5+10+12+14+15=56

sumy=500+400+300+200+100=1500

sumxy=5*500+10*400+12*300+14*200+15*100=14400

sumx²=5²+10²+12²+14²+15²=690

n=5

b=\frac{5(14400)-(56)(1500)}{5(690) -(56)^2}

b=-12000/314

b=-38.217

ybar=a+bxbar

a=ybar-bxbar

ybar=sumy/n=1500/5=300

xbar=sumx/n=56/5=11.2

a=300-(-38.217)(11.2)

a=300+428.025

a=728.025

c)

Selling price y = a - b(age x)

Selling price y = 728.025 - 38.217 age x

d)

SSE known as sum of square of error can be calculated as

SSE=sum(y-yhat)²

y  500 400 300 200 100

x   5      10    12     14    15

yhat= 728.025 - 38.217 age x 536.940  345.855 269.421  192.987  154.770

y-yhat  -36.940  54.145  30.579 7.013  -54.770

(y-yhat)² 1364.56  2931.68  935.08  49.18  2999.75

SSE=sum(y-yhat)²

SSE=1364.56 +2931.68 +935.08 +49.18 +2999.75

SSE =8280.25

4 0
3 years ago
initially, there were the same number of blue marbles and red marbles in a bag. John took out 5 blue marbles and then there were
tester [92]
10 red marbles

Multiply the # of blue marbles by 2 (since there was TWICE as many red marbles), and you have your answer (above)
6 0
4 years ago
Jesse takes his dog and cat to the vet. Jesse's dog weights 23 pounds. the vet tell him his cat weights 5/8 as much as the dog.
Svetradugi [14.3K]
5/8 *23=115/8
115/8 can be simplified to 14 and 3/8
The cat weighs 14 and 3/8 pounds
4 0
3 years ago
Limit   
STatiana [176]

Rationalize the numerator:

\dfrac{\sqrt{x+4}-2}x\cdot\dfrac{\sqrt{x+4}+2}{\sqrt{x+4}+2}=\dfrac{(\sqrt{x+4})^2-2^2}{x(\sqrt{x+4}+2)}=\dfrac x{x(\sqrt{x+4}+2)}=\dfrac1{\sqrt{x+4}+2}

This is continuous at x=0, so we can evaluate the limit directly by substitution:

\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14

5 0
4 years ago
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elena-s [515]

Answer:

frrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr virus don't click ittttttt everyoneeeeeeeeee

have a good day :)

Step-by-step explanation:

6 0
3 years ago
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