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galina1969 [7]
3 years ago
14

A box of soup contains four servings each serving has 4 and 1/2 grams of fat and 720 mg of sodium if someone was really hungry a

nd ate all four servings in the Box how many grams of fat would that person eat
Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

18 Grams of fat that person would have eaten.

Step-by-step explanation:

As one serving has 4 1/2 grams of fat so 4 serving will have 4*(4 1/2).

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The solution shown for the equation is incorrect. What is the correct​ solution? What is the​ error?
Degger [83]
-9(3-r)=45
-27+9t=45
9r=45+27
R=72/9
R=8
The answer is 8 not -8
5 0
3 years ago
Lizards can eat 45 ants per minute. How long would it take to eat 1,080 ants?
dsp73

Answer: 24 minutes!

Step-by-step explanation: As mentioned, it can eat 45 ants per minute, How long would it take to eat 1,080 ants?

It's simple, just divide 1080 by 45 and when you divide it, the answer is 24!

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3 years ago
Resuelve el siguiente problema un buzo en una laguna decendio 8m en una hora.Si cada hora bojo la misma cantidad de metros, ¿cua
S_A_V [24]

Answer:

X = 32 meters.

Step-by-step explanation:

  • Let the unknown distance be X.

<u>Given the following data;</u>

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To find how many meters he would cover in four hours;

1 hour = 8 meters

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Cross-multiplying, we have;

X = 8 * 4

<em>X = 32 meters.</em>

7 0
3 years ago
Which expression is equivalent to 10k+17-7j-18-11k?
balu736 [363]

Answer:

B. -7j-k-1

Step-by-step explanation:

Simplify:

1. IDENTIFY LIKE TERMS

<em>10k</em>+17-7j-18-<em>11k</em>

  • <em>10k and -11k are like terms since they have the same variable.</em>
  • 17 and -18 are like terms since they are regular numbers.
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2. COMBINE LIKE TERMS

-7j-<em>k</em>-1

3 0
3 years ago
Read 2 more answers
How do you solve this? cosθ-tanθcosθ=0
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cos(\theta)=sin(\theta)

Now if we divide with sin on both sides we get:

\frac{cos(\theta)}{sin(\theta)}=1

Now we can remember how cot is defined, it is (cos/sin). So we have:

cot(\theta)=1

Now take the inverse of cot and we get:
\theta=cot^{-1}(1)=\pi\cdot n+ \frac{\pi}{4} , \quad n\in \mathbb{Z}

In general we have cot^{-1}(1)=\frac{\pi}{4}, the reason we have to add pi times n, is because it is a function that has multiple answers, see the picture:

4 0
3 years ago
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