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3 years ago

Please answer! Will give points! Please help!

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

3 0

Answer:

ye its (0,5)

Step-by-step explanation:

Hope it helped you.

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Write in word the following x + 1 > 10

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x = 10

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(5.1×10^15)×(8.1×10^5

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Point A(−5,8) is reflected across the line y = x. What are the coordinates of A′? Show your work and explain.

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Step-by-step explanation:

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prove that if f is integrable on [a,b] and c is an element of [a,b], then changing the value of f at c does not change the fact

Neko [114]

Answer with Step-by-step explanation:

We are given that if f is integrable on [a,b].

c is an element which lie in the interval [a,b]

We have to prove that when we change the value of f at c then the value of f does not change on interval [a,b].

We know that limit property of an integral

$\int_{a}^{b}f dt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$

$\int_{a}^{b} fdt=f(b)-f(a)$ ....(Equation I)

Using above property of integral then we get

$\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$ ......(Equation II)

Substitute equation I and equation II are equal

Then we get

$\int_{a}^{b}fdt= f(c)-f(a)+{f(b)-f(c)}$

$\int_{a}^{b}fdt=f(c)-f(a)+f(b)-f(c)=f(b)-f(a)$

$\int_{a}^{c}fdt+\int_{c}^{b}fdt=f(b)-f(a)$

Therefore, $\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b}fdt$ .

Hence, the value of function does not change after changing the value of function at c.

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3 years ago

Solve for p.<br><br> 12p − 9p − –7p − 8 = –18

Zielflug [23.3K]

Answer:

p=-1

Step-by-step explanation:

12p - 9p --7p -8 =-18

19p-9p-8=-18

10p - 8 = -18

10p = -10

p=-1

5 0

3 years ago