To multiply fracti0ons, we need to convert them to improper fractions:
-2 1/4 = -9/4
-4 1/2 = -9/2
Now, lets multiply:
-9/4 * -9/2 = 81/8
Hope this helps!
Take note that the answer is positive because when multiplying, two negatives make a positive.
Answer:
Step-by-step explanation:
Here, you can use a simple formula.
To find the point of intersection you just put x=0 or y=0.
Because, if a graph intersects x-axis, then at this point y=0
Similarly, if a graph intersects y-axis, then at this point x=0
So, for our given line.
y=-1/4 x +2
when , x=0 , y=-1/4 (0)+2=2
So, the graph intersects y-axis at y=2
when , y=0 ,
then 0=-1/4 x+2
or, 1/4 x=2
or, x=8 [multiplying by 4]
So, the graph intersects x-axis at x=8
Answer:
A = π · (r²)
Step-by-step explanation:
π · r² is the area of a circle.
While π · r² · h can also give you the radius, it can only do so for the Volume
, not the Area
.
doesn't really apply for a circular object, as it requires the length and width. For circular objects, both are equal to the diameter of the object, and 2² · r² · h does not equal the Volume.
π · r³ seems awfully like the volume of a sphere, but there's something missing. The true volume of a sphere is
· π · r³, not
π · r³.
only applies for triangles.
It would be an average of about 8.00 (7.99 to be somewhat exact). You get this by dividing the total amount by 200, the dividing that by 363.
Recall that A = 1/2bh.
We are given that h = 4+2b
So, putting it all together:
168 = 1/2 b(4+2b)
168 = 1/2(4b + 2b^2)
168 = 2b + b^2
b^2 + 2b - 168 = 0.
Something that multiplies to -168 and adds to 2? There's a trick to this.
Notice 13^2 = 169. So, it's more than likely in the middle of the two numbers we're trying to find. So let's try 12 and 14. Yep. 12 x 14 = 168. So this factors into (b+14)(b-12) So b = -14 or b =12. Is it possible to have a negative length on a base? No. So 12 must be our answer.
Let's check this. If 12 is our base, then according to our problem, 2*12 + 4 would be our height... or 28. so what is 12 * 28 /2?
196. Check.
Hope this helped!