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valentinak56 [21]
2 years ago
7

How do I simplify this and explain how and why it makes sense how I found it?

Mathematics
1 answer:
Vsevolod [243]2 years ago
6 0

\sqrt{225 {x}^{2} }  \\  =  \sqrt{15 \times 15 \times x \times x }  \\  = 15x

hope this would help you

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(11 - 8)3 – 2 x 6<br> What is the answer
torisob [31]

Answer:

15

Step-by-step explanation:

3 0
2 years ago
36 even : 12 odd in simplest form
vesna_86 [32]
3 even: 1 odd..................................
7 0
3 years ago
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In the formula l=p+prt, what does l equal when p=500,r=20%, t=2
Juliette [100K]
Just plug in 500 for p, 0.2 for r (because 20% is equivalent to 0.20), and 2 for t:

I=p+prt\\I=(500)+(500)(0.2)(2)\\I=500+200\\I=700

So, if you start with $500 and charge an interest rate of 20% for 2 years, you will gain $200 to get $700 in total.
7 0
3 years ago
The amount of time, in minutes, that a woman must wait for a cab is uniformly distributed between zero and 12 minutes, inclusive
murzikaleks [220]

Answer:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Step-by-step explanation:

Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:

X \sim Unif (a=0, b =12)

And we want to find the following probability:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

7 0
3 years ago
Last year the manager of a health care facility served 36,500 dinners. The manager estimates an increase of 5% in the number of
EastWind [94]

Answer:

38,325 dinners.

Step-by-step explanation:

We have been given that last year the manager of a health care facility served 36,500 dinners. The manager estimates an increase of 5% in the number of dinners to be served next year.

The estimated number of dinners next year would be 36,500 plus 5% of 36,500.

36,500+(\frac{5}{100}\times 36,500)

36,500+(0.05\times 36,500)

36,500+1,825

38,325

Therefore, 38,325 dinners will be served next year.

6 0
3 years ago
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