Least common denominator of those two fractions is 15
Because 15 cant go any less
3 × 1 = 3 15 × 1 = 15
3 × 2 = 6
3 × 3 = 9
3 × 4 = 12
3 × 5 = 15
Answer:
Okay, here's the method I'm going to use.
If you drive north 6 miles, and then drive east 19 miles, you are technically making a triangle.
19 miles
l_______________
6 milesl
l
You are just missing the last side of the triangle: the straight line stretching from across your starting point to the ending point. You can find this by using the Pythagorean theorem.
a^2 + b^2 = c^2
6^2 + 19^2 = c^2
36 + 361 = c
397 = c
= 19.924859
Rounded to the nearest tenth, your answer is
19.9 miles
Answer:
If you want me to turn it into an equation it's: y=12x-1
Step-by-step explanation:
Well, the slope will always be first and you have to put x after it. The y-intercept is always the starting point on a graph, so it'll be last on the equation.
What is NOT true about the solution is that it can have different values
Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have

When t = 0, A(0) = 0 (since the forest floor is initially clear)


So, D = R - A =

when t = 0(at initial time), the initial value of D =
