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3241004551 [841]
3 years ago
14

At a store, customers are randomly selected to participate in a survey. On Friday there were 500 customers at the store. Of thos

e, 90 were selected to participate in the survey. On Saturday, the store manager expects 700 customers in the store. If the probability of being selected to participate in the survey on Saturday is the same as it was on Friday, how many customers will be selected to participate in the survey on Saturday?
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
3 0

Answer:

126 customers

Step-by-step explanation:

90/500=0.18

that means that 18% of all customers were surveyed.

multiplying 700 by 0.18 yields 126, which is your answer!

p.s. this answer got deleted for some stupid reason so i reanswered it

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Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

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Answer:

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Step-by-step explanation:

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Answer: 5 years

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Step-by-step explanation:

Let x represent the number of years and

Let y represent the number of students enrolled

College A: y = 12,300 + 500x

College B: y = 18,550 - 750x

Use substitution Method to solve:

12,300 + 500x = 18,550 - 750x

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Input x = 5 into one of the equations to solve for y.

y = 12,300 + 500x

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