Answer: See explanation
Step-by-step explanation:
Let the cost for insuring the applicant = a.
Let the cost for insuring the spouse = b
Let the cost for insuring the first child= c
Let the cost for insuring the second child = d
A 35-year-old health insurance plan and that of his or her spouse costs $301 per month. This means that:
a + b = $301.
That rate increased to $430 per month if a child were included. This means the cost of a child will be:
= $430 - $301
= $129
The rate increased to $538 per month if two children were included. This means the cost for the second child will be:
= $538 - $430
= $108
The rate dropped to $269 per month for just the applicant and one child. His will be the cost of the applicant and a single child. This can be written as:
a + $129 = $269
a = $269 - $129
a = $140
Since a + b = $301
$140 + b = $301
b = $301 - $140
b = $161
Applicant = $140
The spouse = $161
The first child = $129
The second child = $108
Answer:
(g-f) (-1)= sqrt(15)
(f/g)(-1)= 0
(g+f)(2)=sqrt(3)-3
(g*f)(2)=-3*sqrt(3)
Step-by-step explanation:
We have to eval the expressions given in the point indicated.
Lets start by the first equation
(g-f)(-1)= g(-1) - f(-1)= 
= 
Now, lest continue with the others
(f/g)(-1)= f(-1)/g(-1)= (1-1)/sqrt(15)=0
(g+f)(2)=g(2)+f(2)=sqrt(3)-3
(g*f)(2)=g(2)*f(2)=sqrt(3)*(-3)=-3sqrt(3)
Let's solve your equation step-by-step.
2(3x−1)=−6x−2
Step 1: Simplify both sides of the equation.
2(3x−1)=−6x−2
(2)(3x)+(2)(−1)=−6x+−2(Distribute)
6x+−2=−6x+−2
6x−2=−6x−2
Step 2: Add 6x to both sides.
6x−2+6x=−6x−2+6x
12x−2=−2
Step 3: Add 2 to both sides.
12x−2+2=−2+2
12x=0
Step 4: Divide both sides by 12.
12x/12= 0/12
x=0
Answer:
x=0
HOPE THIS HELPS!!! :)
Answer:
(x, y) ⇒ (x -7, y)
Step-by-step explanation:
The y-coordinates are unchanged. Each x-coordinate of the image is 7 units less than the corresponding pre-image coordinate. As a rule, this is ...
(x, y) ⇒ (x -7, y)
Answer:
$45
Step-by-step explanation:
3/4×60= 45
cost of jacket in sale: $45
hope it helps!
