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inysia [295]
3 years ago
7

Find two numbers, if their sum is 3 and their difference is 21

Mathematics
1 answer:
boyakko [2]3 years ago
4 0

Answer:

The two numbers are -9 and 12

Step-by-step explanation:

-9+12=3 12--9=12+9=21

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A drawing of a sailboat was made useing a restangle and two right triangles, as shown. what is the area of the drawing f the sai
ella [17]

Answer:

45 centimeters squared (45 square centimeters - same thing)

Explanation:

First we need the area of each shape

To find the area of a right triangle we multiply the length of the legs and then divide by 2 - ab/2

Triangle 1: 6 centimeters squared

Triangle 2: 9 centimeters squared

To find the area of a rectangle you multiply the length by the width - lw

Rectangle: 30 centimeters squared

Now we add the values together:

6 + 9 + 30 = 45 centimeters squared

That is my answer, if you need anything else or more clarification I will edit this :)

3 0
3 years ago
Read 2 more answers
Find an equation for the nth term of the arithmetic sequence. -17, -14, -11, -8, ...
igomit [66]
Common difference (d) = - 14-(-17)

d = -14+17
d = 3...

Tn = -17+(n-1)3

Tn = - 17+3(n-1)

Option a is correct.....
7 0
3 years ago
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A farm is to be built in the shape of Quadrilateral ABCD, as shown below. All four sides are equal.
Flura [38]
Area of a rhombus = 1/2 x diagonal 1 x diagonal 2
= 1/2 x 15 1/2 x 13 1/5
= 1/2 x 31/2 x 66/5
=31/2 x 33/5
= 1023/10
= 102.3

Final Answer: 102.3 square feet
4 0
3 years ago
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Solve for x.<br> -15x + 60 ≤ 105 AND 14x + 11 ≤ -31
givi [52]

Answer:

  1. x ≥ -3
  2. x ≥ -3

Step-by-step explanation:

-15x + 60 ≤ 105

-15x ≤ 45

x ≥ -3

14x + 11 ≤ -31

14x ≤ -42

x ≥ -3

Best of Luck!

7 0
2 years ago
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How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?
MAVERICK [17]

Non-negative integers are positive integers or zero.

1. When x_1=0, then there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=10;
  • x_2=1,\ x_3=9;
  • x_2=2,\ x_3=8;
  • x_2=3,\ x_3=7;
  • x_2=4,\ x_3=6;
  • x_2=5,\ x_3=5;
  • x_2=6,\ x_3=4;
  • x_2=7,\ x_3=3;
  • x_2=8,\ x_3=2;
  • x_2=9,\ x_3=1;
  • x_2=10,\ x_3=0.

In total 11 solutions for x_1=0.

2. For x_1=1, there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=9;
  • x_2=1,\ x_3=8;
  • x_2=2,\ x_3=7;
  • x_2=3,\ x_3=6;
  • x_2=4,\ x_3=5;
  • x_2=5,\ x_3=4;
  • x_2=6,\ x_3=3;
  • x_2=7,\ x_3=2;
  • x_2=8,\ x_3=1;
  • x_2=9,\ x_3=0.

In total 10 solutions for x_1=1.

3. This process gives you

  • for x_1=2 - 9 solutions;
  • for x_1=3 - 8 solutions;
  • for x_1=4 - 7 solutions;
  • for x_1=5 - 6 solutions;
  • for x_1=6 - 5 solutions;
  • for x_1=7 - 4 solutions;
  • for x_1=8 - 3 solutions;
  • for x_1=9 - 2 solutions;
  • for x_1=10 - 1 solution.

4. Add all numbers of solutions:

11+10+9+8+7+6+5+4+3+2+1=66.

Answer: there are 66 possible solutions (with non-negative integer variables)

8 0
3 years ago
Read 2 more answers
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