Rotate the hexagon so the sides line up to make it easier
then set up a proportion
x/x+1 = 10/30
30x = 10x + 10
20x = 10
x = 1/2
For c go x positive 1 and go down 2
Y=-x^2-2
dy/dx=-2x and d2y/dx2=-2
Since acceleration is a negative constant, when the velocity equals zero, it will be an absolute maximum for y(x)
dy/dx=0 when -2x=0, x=0
y(0)=-2
So the vertex is at the absolute maximum, which is the point (0,-2)
The answer is B.
If you look for where the two graphs intersect, you'll see that the x values of the ordered pairs are -4 (for the intersection in quadrant 2) and roughly 2.5 (for the intersection in quadrant 4). This problem is just asking you to look for those values.