Can someone please help me with this question?! (geometry)
1 answer:
You might be interested in
Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Step-by-step explanation:
Let a be the price of 1 adult ticket.
Let c be the price of 1 child ticket.
given,
as equation 1,
and
as equation 2.
Now we will solve for a and c using elimination method of simultaneous equations.
Now we multiply equation 2 by 2 to eliminate a and solve for c.
This new equation will be equation 3.
Now we will use equation 1 - equation 3 to eliminate a and solve for c.
Now substitute c into equation 2.
Therefore one adult ticket will cost $17.50 and one child ticket will cost $9.50.