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fiasKO [112]
2 years ago
9

If the midpoint between (18,y) and (20,-15) is (19,-5) find the value of y.​

Mathematics
2 answers:
Kisachek [45]2 years ago
6 0

Answer:

5

Step-by-step explanation:

zlopas [31]2 years ago
5 0

Answer:

What I did was I plotted (20,-15) and (19, -5). From the endpoint to the mid point I got 1 unit to the right and 10 units up. SO I did the same but start at the midpoint and get (18,5).

You might be interested in
Consider this quadratic equation. 2x2 − 1 = 3x + 4 Which equation correctly applies the quadratic formula?
Mariulka [41]

Answer:

\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)}

Step-by-step explanation:

Quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

2x^2-1=3x+4\\\\2x^2-3x-5=0\\\\\\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)} \\\frac{3+-\sqrt{9+40} }{4}

x = \frac{3+-7}{4}

Hope this helps and God bless!

6 0
2 years ago
12. What is the equation of the following parabola?
Vladimir79 [104]

Answer:

c

Step-by-step explanation:

6 0
2 years ago
21x^5y^4-18x^7y^3+15x^2y^5
soldi70 [24.7K]

Do you want us to answer or simplify?

Simplify:=−18x^7  y^3 + 21x^5  y^4+ 15x^2 y^5

5 0
3 years ago
In a group of Explore students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O
Elodia [21]

Answer:

The number of students that like only two of the activities are 34

Step-by-step explanation:

Number of students that enjoy video games, A = 38

Number of students that enjoy going to the movies, B = 12

Number of students that enjoy solving mathematical problems, C = 24

A∩B∩C = 8

Here we have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) -n(A∩C) + n(A∩B∩C)

= 38 + 12 + 24 - n(A∩B) - n(B∩C) -n(A∩C) + 8

Also the number of student that like only one activity is found from the following equation;

n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C) + n(B) - n(A∩B) - n(B∩C) + n(A∩B∩C) + n(C) - n(C∩B) - n(A∩C) + n(A∩B∩C) = 30

n(A) + n(B) + n(C) - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 3·n(A∩B∩C) = 30

38 + 12 + 24 - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 24 = 30

- 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) = -68

n(A∩B) + n(B∩C) + n(A∩C) = 34

Therefore, the number of students that like only two of the activities = 34.

8 0
3 years ago
Make 24 using 1,2,2,7
alexdok [17]
7 times 2=14
14 times 2=24
24 times 1=24
5 0
3 years ago
Read 2 more answers
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