Answer:
z (min) = 705
x₁ = 10
x₂ = 9
Step-by-step explanation:
Let´s call x₁ quantity of food I ( in ou ) and x₂ quantity of food II ( in ou)
units of vit. C units of vit.E Cholesterol by ou
x₁ 32 9 48
x₂ 16 18 25
Objective function z
z = 48*x₁ + 25*x₂ To minimize
Subject to:
1.-Total units of vit. C at least 464
32*x₁ + 16*x₂ ≥ 464
2.- Total units of vit. E at least 252
9*x₁ + 18*x₂ ≥ 252
3.- Quantity of ou per day
x₁ + x₂ ≤ 35
General constraints x₁ ≥ 0 x₂ ≥ 0
Using the on-line simplex method solver (AtoZmaths) and after three iterations the solution is:
z (min) = 705
x₁ = 10
x₂ = 9
Check the picture below.
make sure your calculator is in Degree mode.
2(n - 1) + 4n = 2(3n - 1)
2n - 2 + 4n = 6n -2
6n - 2 = 6n - 2 (equal)
6n - 6n = 2 - 2
0 = 0
whatever value you put into the place of n, you'll get 0 = 0
