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3 years ago

Add: (-6c^5 – 3c – 4) + (5c^5 + 2c – 4). A -2c^5 – c + 5 B-c^5 – c – 8 C-c^5 – ^5c – 8 D-4c^5 – 7c – 4

Mathematics

1 answer:

Shtirlitz [24]3 years ago

6 0

The answer is B.
-6c^5 +5c^5= -c^5
-3c+2c= -c
-4 + -4 = -8

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Arte-miy333 [17]

Answer:

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Step-by-step explanation:

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3 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

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Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

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Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

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Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

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Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

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As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

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High-‐impact aerobics = 1

Low-‐impact aerobics = 4

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3 years ago

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Answer:

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2 years ago

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Eva8 [605]

Answer:

Step-by-step explanation:

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