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Wewaii [24]
2 years ago
6

A sushi restaurant has prepared 24 portions of seafood, five of which had been left out too long and spoiled. If 6 of the 24 por

tions are served randomly to customers, what is the probability that at least one customer will receive spoiled food? (Hint: Consider the complement of this event)
Mathematics
1 answer:
masya89 [10]2 years ago
6 0

Answer:

your answer is 5/6

Step-by-step explanation:

hope it helps

You might be interested in
13, what is the probability that the coin lands on heads the first two times and lands on tales third
lozanna [386]

Answer: The probability is 1/8

Explanation:

Probability is a ratio of the number of relevant outcomes and total number of possible outcomes.

We are flipping the coin three times.

The number of relevant outcomes is 1 (one triple {Head, Head, Tail})

The number of all possible outcomes is the product of 2 possibilities (Head or Tail) on first toss, times another 2 on second, times another 2 on third, so 2^3 = 8.

The probability P = 1/8

4 0
3 years ago
Samuel uses cubes of the same size as the small cubes to make a cuboid twice as long, three times as wide and four times as high
vodka [1.7K]

Answer:

23 more cubes

Step-by-step explanation:

If it's 2 times as long, the length is 2

If it's 3 times as wide, the width is 3

It it's 4 times as high, the height is 4

2 · 3 · 4 = 24, which is 23 more than 1

7 0
3 years ago
{{Geomotry}} <br> please I need help! My math grade depends on it! ;w;
lozanna [386]
This basically means that you have to multiply the x and y values by 3. So 2 time 3 is 6. And -7 times 3 is -21. So the new coordinations are (6, -21)

Hope this helped and pls mark as brainliest!

~ Luna
3 0
3 years ago
Please help!
Anvisha [2.4K]
Ur whole be a for the following reasons
7 0
3 years ago
Squareroot(y-1) + 3 = y
jek_recluse [69]
Note:xy means x times y and x(y) means the same thing

so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0



squareroot(y-1)+3=y

isolate the squareroot
subtrac 3 from boht sides

squareroot(y-1)=y-3

square both sides (since they are equal, you should be able to square both sides and still make it true)

(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5

0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0

therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work



let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true

y=5
7 0
3 years ago
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