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Wewaii [24]
2 years ago
6

A sushi restaurant has prepared 24 portions of seafood, five of which had been left out too long and spoiled. If 6 of the 24 por

tions are served randomly to customers, what is the probability that at least one customer will receive spoiled food? (Hint: Consider the complement of this event)
Mathematics
1 answer:
masya89 [10]2 years ago
6 0

Answer:

your answer is 5/6

Step-by-step explanation:

hope it helps

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Find the inverse of the function and then determine whether the inverse is a function.
nirvana33 [79]
The inverse of this function is not a function and this function isn’t inversable because it’s not one to one
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4 years ago
(x + 1)2 = 25<br> Answer ?!
Ilia_Sergeevich [38]

Answer:

x = 12

Step-by-step explanation:

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3 years ago
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Annie buys some greeting cards. Each card costs $1.75. She pays with a twenty dollar bill.
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3 years ago
The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor
nadya68 [22]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can use as an estimator for p \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

3 0
3 years ago
Find Au B if A ={ 4,7,10,13,17} and B={3,5,7,9}.
Marrrta [24]
Combine the two sets to form one giant set. If needed, toss out any duplicate values.

So,
A U B = {4,7,10,13,17,  3,5,7,9}

Toss out the duplicate item "7" and sort the values to get

A U B = {3,4,5,7,9,10,13,17}
4 0
4 years ago
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