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alexandr1967 [171]
3 years ago
12

Simplify the expression 7√5-3√80​

Mathematics
1 answer:
dolphi86 [110]3 years ago
3 0

Answer:

\boxed{\bold{7\sqrt{5}}}

Step By Step Explanation:

Simplify \bold{3\sqrt{8}\cdot \:0}

\bold{0}

Rewrite Equation

\bold{7\sqrt{5}-0}

Simplify \bold{7\sqrt{5}-0}

\bold{7\sqrt{5}}

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Of the cartons produced by a company, 8% have a puncture, 7% have a smashed corner, and 0.7% have both a puncture and a smashed
Viktor [21]

Answer:

The probability that a randomly selected carton has a puncture or a smashed corner is 0.143

Step-by-step explanation:

we know that P(A∪B) = P(A) + P(B) - P(A∩B).

    since given that P(A) = Probability of getting puncture = 0.08

                                P(B) = probability of getting smashed corner = 0.07

                       P(A∩B) = probability of getting both puncture and smashed corner = 0.007

                    P(A∪B) = probability of getting any of them

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Does the system have one, none or infinite solutions?<br> 8x + 4y = 12<br> y = -2x + 3
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Infinite solutions

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?​
Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

 Given the equation:

\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}

- Using the Difference of squares formula (a^2-b^2=(a+b)(a-b)) we can simplify the denominator of the right side of the equation:

\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}

- Multiply both sides by m-3:

(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)

- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

- Divide both sides of the equation by -6:

\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0

- Factor the equation and solve for "m":

(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

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Answer:

Step-by-step explanation:

because the both times by 6

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