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docker41 [41]
3 years ago
8

Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76

cm2. Now suppose you are asked to enter the answer to two significant figures. (Note that if you do not round your answer to two significant figures, your answer will fall outside of the grading tolerance and be graded as incorrect.)
Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0

Answer:

The area of the rectangle is 12 cm² ⇒ in 2 significant figures

Step-by-step explanation:

* Lets talk about the significant figures

- All non-zero digits are significant

# 73 has two significant figures

- Zeroes between non-zeros digits are significant

# 105.203 has six significant figures

- Leading zeros are never significant

# 0.00234 has three significant figures

- In a number with a decimal point, zeros to the right of the last

 non-zero digit are significant

# 19.00 has four significant figures

- Lets make a number and then approximate it to different significant

∵ 12.7360 has 6 significant figures

∴ 12.736 ⇒ approximated to 5 significant figures

∴ 12.74 ⇒ approximated to 4 significant figures

∴ 12.7 ⇒ approximated to 3 significant figures

∴ 13 ⇒ approximated to 2 significant figures

∴ 10 ⇒ approximated to 1 significant figure

- Another number with decimal point

∵ 0.0546700 has 6 significant figures

∴ 0.054670 ⇒ approximated to 5 significant figures

∴ 0.05467 ⇒ approximated to 4 significant figures

∴ 0.0547 ⇒ approximated to 3 significant figures

∴ 0.055 ⇒ approximated to 2 significant figures

∴ 0.05 ⇒ approximated to 1 significant figures

* Lets solve the problem

∵ The width of the rectangle is 2.1 cm

∵ The length of the rectangle is 5.6 cm

- Area of the rectangle = length × width

∴ Area of the rectangle = 2.1 × 5.6 = 11.76 cm²

- Approximate it to two significant figures

∴ Area of the rectangle = 12 ⇒ to the nearest 2 significant figures

* The area of the rectangle is 12 cm² ⇒ in 2 significant figures

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Answer:

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The function is y=3.75(x)+20 with initial value=20,Jordan puts \$3.75 each week andthe amount saved by Jordan after 52 week =215\$.

Step-by-step explanation:

To understand the slope and y-intercept lets assign x as number of weeks and  y as the money saved by Jordan.

Jordan is already having a sum of \$20 inside the money bank so in 0 week the amount is \$20 can be written as (x,y) =(0,20) in coordinate form.

SImilarly

We have (x,y) =(0,20)and (x_1,y_1) =(25,113.75)

Part A:

The function is y=m(x)+b

From point-slope form,we have slope (m)

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m=\frac{113.75-20}{25-0}=3.75

Y-intercept of this function is the constant term or the money of  \$20 that is already inside the money bank.

We can also calculate y-intercept by arranging the function as b=y-m(x) choosing any (x_1,y_1) = (25,113.75) coordinate and here b is the y-intercept.

The result will be same.

Part B:

The equation <u>y=3.75(x)</u> can represent the function described.

And the initial value is the <u>y-intercept =\$20</u>

Jordan puts<u> 3.75 </u>in his bank each week.

After 52 week the amount saved by Jordan ,here x=52,as the x-variable is the number of weeks.

Plugging the value of x=52 in  y=m(x)+b where m=3.75 so the equation becomes  y=3.75(x)+20

y=3.75(x)+20 =3.75(52)+20=\$215

So basically the function is y=3.75(x)+20 and the amount saved by Jordan after 52 week =215\$.

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\large\boxed{x=1\ \vee\ x=-3i\ \vee\ x=3i}

Step-by-step explanation:

\text{The zeros:}\\\\x^3-x^2+9x-9=0\\\\x^2(x-1)+9(x-1)=0\\\\(x-1)(x^2+9)=0\iff x-1=0\ \vee\ x^2+9=0\\\\x-1=0\qquad\text{add 1 to both sides}\\x-1+1=0+1\\\boxed{x=1}\\\\x^2+9=0\qquad\text{subtract 9 from both sides}\\x^2=-9

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Answer:

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Step-by-step explanation:

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Tan 75 = 17/x

Multiply both sides by x

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x ≈ 4.6

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