Answer: 
This is the same as writing (n-m)/n
Don't forget about the parenthesis if you go with the second option.
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Explanation:
The probability that she wins is m/n, where m,n are placeholders for positive whole numbers.
For instance, m = 2 and n = 5 leads to m/n = 2/5. This would mean that out of n = 5 chances, she wins m = 2 times.
The probability of her not winning is 1 - (m/n). We subtract the probability of winning from 1 to get the probability of losing.
We could leave the answer like this, but your teacher says that the answer must be "in the form of a combined single fraction".
Doing a bit of algebra would have these steps
and now the expression is one single fraction.
Answer:
Let L(n) be the function that gives the amount of logs stacked after n loads.
L(n) = 12 + 8(n-1)
Step-by-step explanation:
Let L(n) be the function that gives the amount of logs stacked after n loads.
Let's call for the moment the first load as L(0)
L(0)= 12
Let r be the number of logs carried in each load, then
L(n) = 12 + nr
Since L(6) (the seventh load) equals 60, we have
60 = 12 + 6r, and r = 8.
So a function for the number of loads starting from n=0 would be
L(n) = 12 + 8n
If we want to start with n=1, we simply change the variable
L(n) = 12 + 8(n-1) (n=1,2,3,...).
So L(1) = 12, L(2) = 20, L(3) = 28,...L(7) = 60 and so on.
Answer:
$286
Step-by-step explanation:
396/18 = $22 per hr x 13 hrs = $286
Plz give Brainliest
This will generate a line quickly dropping from left to right, with an x-intercept of 0.4 and a y-intercept of 2.
See the attached image for the actual graph.
Sin (A + B) = sin A cos B + cos A Sin B
<span>Cos (A - B) = cos A cos B + sin A sin B </span>
<span>=> (SinACosB+ CosASinB) (CosACosB +SinASinB) </span>
<span>=>SinACosACos^2B+Sin^2ACosBSinB+Cos^2A... </span>
<span>=>SinACosA(Cos^2B+Sin^2B) +SinBCosB(Sin^2A+Cos^2A) </span>
<span>we know that Sin^2+Cos^2=1 </span>
<span>=>SinACosA(1)+SinBCosB(1) </span>
<span>=SinACosA+SinBCosB </span>
<span>Proved
</span>
