GIVEN: ∠D congruent to ∠T, ∠E congruent to ∠U, DE congruent to UT
2 answers:
<span>GIVEN:
Answer: ASA Postulate
Step-by-step explanation:
GIVEN : ∠D congruent to ∠T,
∠E congruent to ∠U,
DE congruent to UT
Now, in ΔUXT and ΔDOE
∠D congruent to ∠T [Angle]
DE congruent to UT [included side]
∠E congruent to ∠U [Angle]
By ASA postulate of congruence , ΔUXT ≅ ΔDOE
ASA Postulate of congruence says that if two angles and the included side of a triangle are congruent to two angles and the included side of other triangle then the triangles are said to be congruent.
You might be interested in
-4r-24=-63
Let the number of pages read on day 1 be = x
Then on day 2 he read twice the pages from day one, it is = 2x
On 3rd day he read 6 pages less than 1st day, it is = x-6
Total pages are = 458
The equation becomes:
So on the third day, Aiden read
Answer:
<u>5x+13</u> ÷ 36 = 6x-2 ÷ 30
5x+13 ÷ 6 = 6x-2 ÷ 5
25x+65=36x-12
11x=77 → x=7
<u />
Step-by-step explanation:
Answer:
To avoid expansion, you can just use the power of a power rule and multiply the two exponents from the start.
Step-by-step explanation:
(<em>x</em>^4)^3
= <em>x</em>^4×3
= <em>x</em>^12
Part A) y = 2x
