9514 1404 393
Answer:
k = -1
Step-by-step explanation:
Put the given value of x in the equation, and solve the resulting equation for k.
2(5 -3) +k(1 +2·5) = k - 5 - 1
2(2) +k(11) = k -6 . . . . simplify a bit
10k = -10 . . . . . . . . . . add -4-k to both sides
k = -1 . . . . . . . . . . . . . divide by 10
The value of k is -1.
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<em>Check</em>
Use k = -1 in the original equation and solve for x.
2(x -3) -(1 +2x) = -1 -x -1
2x -6 -1 -2x = -x -2 . . . . eliminate parentheses
x = 7 -2 = 5 . . . . . . add x+7; answer checks OK
Volume = 10,700
V = LWH
L = 29.4
W = 16.7
H = 21.8
All we need to do is multiply them all together and then round the answer to get our final answer to the hundreds place.
V = LWH
V = 29.4(16.7)(21.8)
V = 490.98(21.8)
V = 10703.364
Then, we need to round it to the hundreds place.
V = 10,700
Answer:
The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Step-by-step explanation:
Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.
If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.
Compute the value of P (X < 325) as follows:
Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Answer:
C)2 : 1
Step-by-step explanation:
AEFG ≈ ALMN
FG / MN = 4 / 2 = 2/1
So the ratio of AEFG to ALMN = 2 / 1 or 2 : 1
