Answer:
220
Step-by-step explanation:
110 cannot be the lcm for 20 but 10 and 110
so 220 can be the lcm for 20, 10, and 110
hope this helps
For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
4% of the run is 200
as an equation 4%=0.04
0.04*run=200
so run=200/0.04
run=5000feet
Answer:
Charlie's solution is incorrect.
Part A: The equation must be divided by the number next to the variable. So 5x will be divided by 5 which will equal x, and 30 will be divided by 5 which equals 6. The final answer will be x=6.
Part B: The equation will have one solution because there is only one way to solve it.
216/ 120 times 90 divided by 18 times 5 and the answer is 45
