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Klio2033 [76]
3 years ago
12

Can somebody help me with these please

Mathematics
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

<h3>No solutions:                         5 - 4 + 7x + 1 = 7x + 1</h3><h3>One solution:                        5 - 4 + 7x + 1 = 2x + 1</h3><h3>Infinitely many solutions:    5 - 4 + 7x + 1 = 7x + 2</h3>

Step-by-step explanation:

left side:   5 - 4 + 7x + 1 = 1 + 7x + 1 = 7x + 2

<u>No solution</u> is when we have the same number of x-es and different sums of other numbers on both sides of equation. So we have to put 7 next to x and any numer except 2 at the second place.

So the right side could be 7x+1 or 7x+3 or 7x+125 and so on.

<u>One solution</u> is when we have different number of x-es on both sides of equation. The sums of other numbers could be any numbers.

So the right side could be ex.: 2x+1, x+2, 8x, 3x+(-18), and so on.

<u>Infinitely many solutions</u> is when we have  the same number of x-es and the same sums of other numbers on both sides of equation. So we have to put 7  next to x and numer 2 at the second place.

So the right side has to be 7x + 2

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