All categories

3 years ago

PLEASE HELP I SUCK AT DECIMALS AND FRACTIONS

Mathematics

1 answer:

vlabodo [156]3 years ago

3 0

Answer:

-37/99 is the simplest form. Hope this helps.

You might be interested in

PLEASE HELP ME!!!! Please show work!!! ASAP!!

Ber [7]

The answer would be C. because you have to multiply all of the numbers and then divide by the 90 degree angle.

5 0

3 years ago

A hockey team scored 45 goals in its first 16 games. At this rate, how many goals would the team score in an 80 game season? A.

Goshia [24]

First you have to divide 45 by 16. that gives us 2.8125. then multiply 2.8125 by 80 to get 225.

6 0

3 years ago

4 to the seventh power over 5 squared all raised to the third power

Komok [63]

(4^7 / 5^2)^3

= 4^21 / 5^6

Answer

4^21 / 5^6

3 0

3 years ago

Read 2 more answers

What are two ratios equivalent to 10:85

guajiro [1.7K]

Answer:

2 : 17

1 : 8.5

6 0

3 years ago

The J.O. Supplies Company buys calculators from a non-US supplier. The probability of a defective calculator is 10 percent. If 3

RSB [31]

Answer:

There is a 24.3% probability that one of the calculators will be defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability of a defective calculator is 10 percent.

This means that $p = 0.1$

If 3 calculators are selected at random, what is the probability that one of the calculators will be defective

This is P(X = 1) when n = 3. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.1)^{3}.(0.9)^{2} = 0.243$

There is a 24.3% probability that one of the calculators will be defective.

3 0

3 years ago