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Fynjy0 [20]
3 years ago
15

PLEASE HELP I SUCK AT DECIMALS AND FRACTIONS

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

-37/99 is the simplest form. Hope this helps.

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10% of Kindergarteners know how to read before school starts. If there are 150 kindergarteners at a
Tamiku [17]

Answer:

15

Step-by-step explanation:

To get 10 percent, you divide by 10.

150 divided by 10 equals 15.

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3 years ago
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The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
3 years ago
If p = 2 and q = 8, the value of p3 + V64 q ls____​
gavmur [86]

Answer:

518

Step-by-step explanation:

P = 2

Q = 8

p3 + 64q

Multiply "p" (which is 2) with 3

Multiply "q" (which is 8) with 8

Add the two numbers you get

And you have you answer

I hope this helps. :)

4 0
3 years ago
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Can’t read the paper sry try again please
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This is part two of the problem go check part one so it makes sense
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Answer:Execute Order 66

Step-by-step explanation:

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