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kondaur [170]
2 years ago
5

Geometric Sequence Pre-Calc Please help with questions highlighted in red

Mathematics
1 answer:
il63 [147K]2 years ago
7 0
Yeap, number 6 is growing the fastest, because 1.189 is the largest of the growth factor, now that's just the growth factor, no the growth rate.

growth rate will be 1.189 - 1, or 0.189, in decimal format, let's put it in percentage format, 0.189 * 100, or 18.9%.

and yes, you're correct again, 3 is shrinking fastest, because 0.78 is the smallest growth factor, so its growth rate is

0.78 - 1, or -0.22, is a negative rate, so if we put in decay term is just 0.22 in decimal format, let's put it in percentage format

0.22 * 100, or 22%.
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Judah's family wants to ride the bumper boats at a water park. There are 4 children (c) and 2 adults 9 (a) in Judah's family. Th
zhannawk [14.2K]

Answer:

Yes, the boats are safe to ride.

Step-by-step explanation:

40 (4) + 12 (2) ≤ 500

160 + 24 ≤ 500

184  ≤ 500

184 is less than 500.

because I was not sure if you had 9 adults instead of 2, this is the answer:

40 (4) + 12 (9) ≤ 500

160 + 108 ≤ 500

268 ≤ 500

268 is less than 500

3 0
2 years ago
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Find the perimeter of the sector of a circle of radius 14cm with an angle of 72 degree
Alika [10]

Answer:

the area sector is 123.2

7 0
3 years ago
41:41
Minchanka [31]

Answer:

Answer: B

Step-by-step explanation:

just solve keep up learning!

6 0
3 years ago
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TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN
stich3 [128]

Answer:

<u>A.</u> <u>It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

<u>It would be needed 20 packets to transmit 30,000 bytes of information</u>

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

<u>45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Note: Same answer provided to question 14037480, answered by me.

7 0
3 years ago
What is the common ratio of the geometic sequence whose second and forth terms are 6 and 54, respectively?
Luda [366]

Answer:

C

Step-by-step explanation:

The n th term formula of a geometric sequence is

a_{n} = a r^{n-1}

where a is the first term and r the common ratio

Using the second and fourth term, then

ar = 6 → (1)

ar³ = 54 → (2)

Divide (2) by (1)

\frac{ar^3}{ar} = \frac{54}{6} = 9

r² = 9 ⇒ r = \sqrt{9} = 3 → C

7 0
2 years ago
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