The least common multiple would be 240.
120(2)=240 AND
80(3)=240
Answer:
The measures of the angles at its corners are 
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the measure of angle A
Applying the law of cosines


![cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))](https://tex.z-dn.net/?f=cos%28A%29%3D%20%5B215%5E%7B2%7D%2B125%5E%7B2%7D-185%5E%7B2%7D%5D%2F%282%28215%29%28125%29%29)


step 2
Find the measure of angle B
Applying the law of cosines


![cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))](https://tex.z-dn.net/?f=cos%28B%29%3D%20%5B215%5E%7B2%7D%2B185%5E%7B2%7D-125%5E%7B2%7D%5D%2F%282%28215%29%28185%29%29)


step 3
Find the measure of angle C
Applying the law of cosines


![cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))](https://tex.z-dn.net/?f=cos%28C%29%3D%20%5B125%5E%7B2%7D%2B185%5E%7B2%7D-215%5E%7B2%7D%5D%2F%282%28125%29%28185%29%29)


Respuesta:
Kansas, Misuri = 8
Paradise, Michigan = 3
Explicación paso a paso:
El rango intercuartílico (IQR) = Q3 - Q1
Q3 = 3/4 (n + 1) th término
n = número de muestras
Q1 = 1/4 (n + 1) th término
Kansas Misuri:
23,25,28,28,32,33,35
Datos pedidos: 23, 25, 28, 28, 32, 33, 35
n = 7
Q1 = 1/4 * 8 = 2do trimestre = 25
Q3 = 3/4 * 8 = 6. ° tem = 33
Q1 = 33 - 25 = 8
Paradise, Michigan:
16,24,26,26,26,27,28
Datos pedidos: 16,24,26,26,26,27,28
Q1 = 1/4 * 8 = 2do = 24
Q3 =. 3/4 * 8 = 6to = 27
Q3 - Q1 = 27 - 24 = 3
Answer:
<h3>Surface Area = 1,256 cm</h3>
<u>Solution:</u>
formula: Surface Area of a Sphere: 4π · r²
Surface area = 4π · r²
SA = 4(3.14) (10)²
SA = (12.56)(100)
SA = 1,256