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Butoxors [25]
3 years ago
11

Solve 38x21 using an area model

Mathematics
1 answer:
Lena [83]3 years ago
8 0
38×21=798
I used area model idk if u were asking a different person
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Yo help please i’ll give u a brainliest no links i just need the correct answer
Valentin [98]
The cylinder has a greater volume
5 0
3 years ago
1. A magazine reported 66% of all dog owners usually greet their dog before greeting their
NISA [10]

Answer:

(a) There is 95% confidence that the true proportion of dog owners who greet their dogs first is between 0.475 and 0.775.

(b) The point estimate is 0.625. The margin of error is 0.15.

(c) It is plausible that the true proportion of all owners who greet their dog first is 66%.

Step-by-step explanation:

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval. Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

In statistic, point estimation comprises of the use of sample data to estimate a distinct data value (known as a point estimate) which is to function as a "best guess" or "best estimate" of an unidentified population parameter. The point estimate of the population mean (µ) is the sample mean (\bar x).

The  (1 - α)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\times \sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error for this interval is:

MOE=\frac{UL-LL}{2}

For the hypothesis test, if the confidence interval consist of the null value of the parameter then the null hypothesis is accepted or else rejected.

The 95% confidence interval for the population proportion of owners who greet their dog first is,

CI = (0.475, 0.775)

(a)

The 95% confidence interval for the population proportion, (0.475, 0.775), implies that there is a 0.95 probability that the true proportion of dog owners who greet their dogs first is between 0.475 and 0.775.

Or, there is 95% confidence that the true proportion of dog owners who greet their dogs first is between 0.475 and 0.775.

(b)

The point estimate of the population proportion (<em>p</em>) is the sample mean (\hat p).

Compute the point estimate from the 95% confidence interval as follows:

Point estimate = (UL + LL)/2

                        =\frac{0.775+0.475}{2}\\=0.625

The point estimate is 0.625.

Compute the margin of error as follows:

MOE=\frac{UL-LL}{2}=\frac{0.775-0.475}{2}=0.15

The margin of error is 0.15.

(c)

The hypothesis to test whether the proportion of all owners who greet their dog first is 66% is:

<em>H₀</em>: The proportion of all owners who greet their dog first is 66%, i.e. <em>p</em> = 0.66

<em>Hₐ</em>: The proportion of all owners who greet their dog first is not 66%, i.e. <em>p</em> ≠ 0.66.

The 95% confidence interval for the population proportion of owners who greet their dog first is,

CI = (0.475, 0.775)

The 95% confidence interval consists of the null value, i.e. <em>p</em> = 0.66.

The null hypothesis was failed to rejected.

Thus, it is plausible that the true proportion of all owners who greet their dog first is 66%.

6 0
3 years ago
What is the cost of paving the path with bricks at rate of Rs.100 per m². When area of land is 63 m s
Mademuasel [1]

Answer:

Rs. 6300

Step-by-step explanation:

Given that:

Land area = 63m²

Rate of paving brick = RS. 100 per m²

Hence, to pave bring on a 63m² land area ;

Total cost of paving brick will be :

Cost per m² * land area

Rs. 100 * 63

= Rs. 6300

8 0
3 years ago
Help pleaseeee!!!!!! 30 points​
nasty-shy [4]

Answer:

Pen = y

25.00 + y

Step-by-step explanation:

expressions do not have equal signs.

25 more than the pen is 25 + y

the expression would be

25 + y

4 0
3 years ago
Read 2 more answers
Ari bought a DVD that originally cost $15 on sale for 20% off. The sales tax is 5%. How much did Ari pay for the DVD, including
Ugo [173]
20% off of $15 is 12.00
And 5% of 12.00 is .60
So your answer is $12.60
If this helps mark as brainliest pls
4 0
3 years ago
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