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Anna007 [38]
3 years ago
15

Happy May 4th everyone also known as May the 4th be with you or as i like to call it star wars day!

Mathematics
2 answers:
stira [4]3 years ago
8 0

Answer:

yayy

Step-by-step explanation:

kifflom [539]3 years ago
4 0

Same to u

ajajjaoqkqmanahahhqkakaka

ajajjakamammama

You might be interested in
For the function defined by f(t)=2-t, 0≤t<1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

5 0
3 years ago
Explain why parallelograms are always
Mars2501 [29]

Answer: Parallelogram is a kind of quadrilateral where as there are some quadrilaterals (like trapezoid , kite, .. ) that do not satisfy the properties of parallelograms.

Step-by-step explanation:

A quadrilateral is a closed polygon having fours sides.

A parallelogram is a kind of quadrilateral having following properties:

Its opposite sides and opposite angles are equal.

The sum of adjacent angles is 180°.

The diagonal of parallelogram bisect each other.

A Trapezoid is also a quadrilateral . It has only one pair of parallel sides. (The other one are not parallel).

So , all quadrilaterals not parallelograms.

Therefore, parallelograms are always quadrilaterals but quadrilaterals are sometimes parallelograms because parallelogram is a kind of quadrilateral where as there are some quadrilaterals (trapezoid , kite, .. ) ) that do not satisfy  the properties of parallelograms.

plz mark me as brainliest :)

6 0
3 years ago
What is 3(6 – m) – 10 =
PIT_PIT [208]

Answer:

it's 8-3m

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=9x-3%20%5Cleqslant%2011x%20-%203" id="TexFormula1" title="9x-3 \leqslant 11x - 3" alt="9x-3 \l
AURORKA [14]

Answer:

0 ≤x

Step-by-step explanation:

9x-3 ≤11x-3

Subtract 9x from each side

9x-9x-3 ≤11x-9x-3

-3 ≤2x-3

Add 3 to each side

-3+3 ≤2x

0 ≤2x

Divide by 2

0/2 ≤2x/2

0 ≤x

6 0
3 years ago
There was 2/3 of a pan of a lasagna in the refrigerator. Bill and his friends ate half of what was left. Write a number sentence
olga nikolaevna [1]
Bill and his friends ate 1/3 of the pan, you get this by doing: 2/3 / 1/2 = 1/3 or 0.3333
7 0
3 years ago
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