Answer:
Generally, K+ ions ensures re-polarization of the membrane potential. It always ensures that the neuron returns its resting state, protecting the neurons and ensuring episode of rest before the next action potential.
K+ does this by leaving the axon, making the inner layer more negative. This is resting membrane potential. Because there are many K+ channels for leakages out of the neuronal axons.
Therefore, in this scenario, he neuron will return to its resting membrane potential state which between values -50 to -75mV.
Therefore the value of the potential will be -60mV, or within the range of -50 to -60mV. This is because the neuron is is non- excitable.
Explanation:
Answer:
Explanation:
- <u>A Lake Is -Not- A Biome</u>
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Biomes: T<u>emperate Deciduous Forest, Coniferous Forest, Woodland, Chaparral, Tundra, Grassland, Desert, Tropical Savanna</u>
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A lake is not a biome. A lake can be found in a biome, but a lake is not itself a biome. A biome is a community of plants and animals that have common characteristics for the environment they exist in. Yes, similar species can be found living in a lake, but a lake can be found in a particular biome where there are lots more of the same species.
- Mordancy
Patty (age 7) has symptoms that include a skin rash, fever slowed growth, fatigue, and swelling in the joints. She was diagnosed as having juvenile rheumatoid arthritis.
What is juvenile rheumatoid arthritis described as?
Juvenile rheumatoid arthritis is the most common kind of arthritis in children. It is characterized by heat and discomfort and causes the joints to expand. The duration of acute arthritis can range from a few weeks or months to years or even a lifetime. It can also be persistent. IA types include autoimmune and autoinflammatory illnesses. This suggests that the immune system, which is meant to fight off viruses and pathogens, becomes confused and attacks the body's cells and tissues. The doctor can suggest blood testing for C-reactive protein and erythrocyte sedimentation rate. These blood tests evaluate inflammatory markers or markers of inflammation.
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The extracellular glucose inhibit transcription of the lac operon (D) by reducing the levels of intracellular cAMP.
Lac operon is the assembly of various genes that are involved in the uptake and metabolism of lactose of E. coli or any other bacteria. It consists of a regulator gene, promoter gene, operator and structural gene. Structural genes are three: z, y and a. Each codes for a different enzyme.
cAMP is the cyclic Adenosine Monophosphate. It is produced by the bacteria when there are low levels of glucose in it. Hence it is also named as hunger signals. Therefore, cAMP is responsible for activating the operon to produce lactose.
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The answer is D.They reproduce independently. It is false because they need a host and can't survive by themselves.
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