Answer:
Hey there!
The circumference of a circle is 
, where d is the diameter, and 
is a constant roughly equal to 3.14.
The diameter is 16, so plugging this into the equation, we get 3.14(16)=50.24.
The circumference of the circle is 50.24 yards.
Hope this helps :)
Answer:
see explanation
Step-by-step explanation:
To find the y-intercept let x = 0, in the equation
6x - 3y = 15 → (1)
x = 0 : - 3y = 15 ⇒ y = - 5 ⇒ (0, - 5) ← y- intercept
x + 3y = - 8 → (2)
x = 0 : 3y = - 8 ⇒ y = -
⇒ (0, - ) ← y- intercept
Hello,
Use the factoration
a^2 - b^2 = (a - b)(a + b)
Then,
x^2 - 81 = x^2 - 9^2
x^2 - 9^2 = ( x - 9).(x + 9)
Then,
Lim (x^2- 81) /(x+9)
= Lim (x -9)(x+9)/(x+9)
Simplity x + 9
Lim (x -9)
Now replace x = -9
Lim ( -9 -9)
Lim -18 = -18
_______________
The second method without using factorization would be to calculate the limit by the hospital rule.
Lim f(x)/g(x) = lim f(x)'/g(x)'
Where,
f(x)' and g(x)' are the derivates.
Let f(x) = x^2 -81
f(x)' = 2x + 0
f(x)' = 2x
Let g(x) = x +9
g(x)' = 1 + 0
g(x)' = 1
Then the Lim stay:
Lim (x^2 -81)/(x+9) = Lim 2x /1
Now replace x = -9
Lim 2×-9 = Lim -18
= -18
You're so pointless ... duh XD
Answer:
m∠P ≅ m∠L; this can be confirmed by translating point P to point L.
Step-by-step explanation:
Angle angle (AA) similarity postulate state that two triangles are similar if two of their corresponding angle is similar. The corresponding angle for each point of the triangles will be:
∠L=∠P
∠Q=∠M
∠N=∠R
Since the 2nd triangle made from dilation, it should maintain its orientation.
Option 1 is true, ∠P corresponds to ∠L. If you move/translate point P to point L, you can confirm it because their orientation is the same.
Option 2 is false, the triangle will be similar if ∠P=∠N but you can't confirm it with translation alone.
Option 3 and 4 definitely wrong because it speaking about length, not the angle.
