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brilliants [131]
3 years ago
6

The scatter chart below displays the residuals verses the dependent variable, x. Which of the following conclusions can be drawn

based upon this scatter chart? a. The residuals are normally distributed. b. The model over predicts the value of the dependent variable for small values and large values of the independent variable. c. The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship. d. The residuals have a constant variance.
Mathematics
1 answer:
lawyer [7]3 years ago
6 0

Answer: Hello the scatter plot related to your question is missing attached below is the scatter plot

answer :  The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship ( C )

Step-by-step explanation:

The conclusion that can be drawn based upon the scatter chart is that The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship

<em>A scatter plot helps in observing the relationship within different numeric variables but the scatter plot attached fails in the showing the actual relationship </em>

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Answer:

a^2 - 3

Step-by-step explanation:

(3a^2 + 1) - (4 + 2a^2)

3a^2 + 1 - 4 - 2a^2

a^2 - 3

8 0
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Can someone pls help need it ASAP and can you pls explain in full detail how to do it
GenaCL600 [577]

Answer:

x= 1 , y=4

Step-by-step explanation:

x-y= -3 => Equation 1

x+5y= 21 => Equation 2

<u>Substitut</u><u>ion</u><u> </u><u>Method</u><u>:</u>

<u>Substitu</u><u>te</u><u> </u><u>Equation</u><u> </u><u>1</u>=>

x=y-3 <= Equation 3

Put x=y-3 in Equation 2:

x+5y=21

( y-3)+5y=21

y-3+5y=21

6y-3=21

6y=21+3

6y=24

y=24÷6

y=4

Put y=4 in Equation 1:

x-y= -3

x-4=-3

x=4-3

x=1

Hope this helps :)

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Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
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