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Masja [62]
3 years ago
10

Use the regression calculator to compare the teams’ number of runs with their number of wins.

Mathematics
2 answers:
Scilla [17]3 years ago
8 0

Answer:

-23.21

there should be a two part for this and the answer would be D y= 0.15x - 23.21

Step-by-step explanation:

Yanka [14]3 years ago
5 0

Answer:

-23.21

Step-by-step explanation:

Edge 2021

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Simplify:<br> -3(x – 4) +3(y - 6)
Elodia [21]

Answer:

Let's simplify step-by-step.

−3(x−4)+3(y−6)

Distribute:

=(−3)(x)+(−3)

(−4)+(3)(y)+(3)(−6)=−3x+12+3y+−18

Combine Like Terms:

=−3x+12+3y+−18=(−3x)+(3y)+( 12+18)=−3x+3y+−6

Answer:

=−3x+3y−6

Can I have a brainliest

Step-by-step explanation:

8 0
3 years ago
1. Solve. 3(h – 4) = –1/2(24 – 6h)<br><br> 2. Solve for x. ax + bx = –c
Naddik [55]
ANSWER TO QUESTION 1

3(h-4) = - \frac{1}{2} (24 - 6h)

We multiply through by the Least Common Multiple which is 2.

2 \times 3(h-4) = - 2 \times \frac{1}{2} (24 - 6h)

6(h - 4) = - 1(24 - 6h)

We expand brackets to obtain,

6h - 24 = - 24 + 6h

Grouping like terms, have

6h - 6h = - 24 + 24

\Rightarrow 0 = 0

Whenever you solve an equation and you get the above result, you don't have to get confuse.

It simply means the question does not have a UNIQUE solution.

That any real number will number will satisfy the above equation.

Hence,

h \in R




ANSWER TO QUESTION 2

ax + bx = - c

We factor x to obtain;

x(a + b) = - c

We divide both sides by (a+b)

x = - \frac{ c}{a + b}
3 0
3 years ago
Let f be the function defined by f(x)=cx−5x^2/2x^2+ax+b, where a, b, and c are constants. The graph of f has a vertical asymptot
Musya8 [376]

Answer:

a) a = 2 and b = -4, b) c = -10, c) f(-2) = -\frac{5}{3}, d) y =  -\frac{5}{2}.

Step-by-step explanation:

a) After we read the statement carefully, we find that rational-polyomic function has the following characteristics:

1) A root of the polynomial at numerator is -2. (Removable discontinuity)

2) Roots of the polynomial at denominator are 1 and -2, respectively. (Vertical asymptote and removable discontinuity.

We analyze each polynomial by factorization and direct comparison to determine the values of a, b and c.

Denominator

i) (x+2)\cdot (x-1) = 0 Given

ii) x^{2} + x-2 = 0 Factorization

iii) 2\cdot x^{2}+2\cdot x -4 = 0 Compatibility with multiplication/Cancellative Property/Result

After a quick comparison, we conclude that a = 2 and b = -4

b) The numerator is analyzed by applying the same approached of the previous item:

Numerator

i) c\cdot x - 5\cdot x^{2} = 0 Given

ii) x \cdot (c-5\cdot x) = 0 Distributive Property

iii) (-5\cdot x)\cdot \left(x-\frac{c}{5}\right)=0 Distributive and Associative Properties/(-a)\cdot b = -a\cdot b/Result

As we know, this polynomial has x = -2 as one of its roots and therefore, the following identity must be met:

i) \left(x -\frac{c}{5}\right) = (x+2) Given

ii) \frac{c}{5} = -2 Compatibility with addition/Modulative property/Existence of additive inverse.

iii) c = -10 Definition of division/Existence of multiplicative inverse/Compatibility with multiplication/Modulative property/Result

The value of c is -10.

c) We can rewrite the rational function as:

f(x) = \frac{(-5\cdot x)\cdot \left(x+2 \right)}{2\cdot (x+2)\cdot (x-1)}

After eliminating the removable discontinuity, the function becomes:

f(x) = -\frac{5}{2}\cdot \left(\frac{x}{x-1}\right)

At x = -2, we find that f(-2) is:

f(-2) = -\frac{5}{2}\cdot \left[\frac{(-2)}{(-2)-1} \right]

f(-2) = -\frac{5}{3}

d) The value of the horizontal asympote is equal to the limit of the rational function tending toward \pm \infty. That is:

y =  \lim_{x \to \pm\infty} \frac{-10\cdot x-5\cdot x^{2}}{2\cdot x^{2}+2\cdot x -4} Given

y =  \lim_{x \to \infty} \left[\left(\frac{-10\cdot x-5\cdot x^{2}}{2\cdot x^{2}+2\cdot x-4}\right)\cdot 1\right] Modulative Property

y =  \lim_{x \to \infty} \left[\left(\frac{-10\cdot x-5\cdot x^{2}}{2\cdot x^{2}+2\cdot x-4}\right)\cdot \left(\frac{x^{2}}{x^{2}} \right)\right] Existence of Multiplicative Inverse/Definition of Division

y =  \lim_{x \to \pm \infty} \left(\frac{\frac{-10\cdot x-5\cdot x^{2}}{x^{2}} }{\frac{2\cdot x^{2}+2\cdot x -4}{x^{2}} } \right)   \frac{\frac{x}{y} }{\frac{w}{z} } = \frac{x\cdot z}{y\cdot w}

y =  \lim_{x \to \pm \infty} \left(\frac{-\frac{10}{x}-5 }{2+\frac{2}{x}-\frac{4}{x^{2}}  } \right)   \frac{x}{y} + \frac{z}{y} = \frac{x+z}{y}/x^{m}\cdot x^{n} = x^{m+n}

y =  -\frac{5}{2} Limit properties/\lim_{x \to \pm \infty} \frac{1}{x^{n}}  = 0, for n \geq 1

The horizontal asymptote to the graph of f is y =  -\frac{5}{2}.

4 0
4 years ago
A circumference of 320 cm what is the radius
alina1380 [7]
Radius = 50.93

Diameter = 101.86

Area = 8148.87
7 0
2 years ago
√−100 = _+ _i Fill in the blank
kifflom [539]

Step-by-step explanation:

\sqrt{ - 100}  =  \sqrt{ - 1}  \times  \sqrt{100}  \\  =  \sqrt{100} i \\  = 10i \\  = 0 + 10i

7 0
3 years ago
Read 2 more answers
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