X = smaller number, y = larger number
x + y = 15.....x = 15 - y
4x = 2y - 60
4(15 - y) = 2y - 60
60 - 4y = 2y - 60
60 + 60 = 2y + 4y
120 = 6y
120/6 = y
20 = y <==== larger number is 20
x + y = 15
x + 20 = 15
x = 15 - 20
x = - 5
Well to find distance subtract A. and B. from each other this should give you (340,370). Subtracting this is the quickest way to find range.
Answer:
Step-by-step explanation:
For any angle 
, we have that:
Quadrant:
means that is in the first quadrant. This means that both the sine and the cosine have positive values.
Find the cosine:
Since the angle is in the first quadrant, the cosine is positive.
Since both are equivalent to y, the equations must be equivalent.
x^2-x-3= -3x+5
x^2+2x-8=0
(x+4)(x-2)=0
x=-4, x=2
Plug the values of x in to either equation
y=-3(-4)+5
y= 12+5
y=17
y= -3(2)+5
y=-6+5
y=-1
Final answer: (-4,17) and (2,-1)
Answer:
Figure it out dummy
Step-by-step explanation:
