How many different three colour flags (tricolors) can be designed using
green, blue, red, yellow and black stripes if all three colours must be
different?
6P3 = 6!/(6 - 3)! = 6!/3! = (6 x 5 x 4 x 3 x 2 x 1)/(3 x 2 x 1) = 720/6 = 120 flags.
How many of them contain a red stripe?
The remaining two colours can be arranged in 5P2 = 5!/(5 - 2)! = 5!/3! = (5 x 4 x 3 x 2 x 1)/(3 x 2 x 1) = 120/6 = 20ways
The red stripe can arranged in 3 ways
Therefore, number of flags having red stripe is 20 x 3 = 60 flags.
3X+9X=180
12X=180
X=15°
Angle 1=3X
Angle 1 =45°
That's your answer.
4 3/4 divided by 5/8 equals 19/4 divided by 5/8 equals 19•8/4•5 equals 152/20 equals 7 3/5