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IgorLugansk [536]
3 years ago
7

Find the value of x for which l is parallel to m

Mathematics
1 answer:
laila [671]3 years ago
6 0

If it is parallel then x would be A) 28

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Find the distance between the points <br><br>(−5,2) and (9.2)<br>​
forsale [732]

Step-by-step explanation:

<u>Formula</u><u> </u><u>U</u><u>s</u><u>e</u><u>d</u>

<u>By distance formula,</u>

  • d (A,B)=√[(x₁ - x₂)² + (y₁ - y₂)²]

\sf \longmapsto \: D = √(x2-x1)²+(y2-y1)²

\sf \longmapsto= √(9+5)²+(2-2)²

\sf \longmapsto= = √14²+09

\sf \red \longmapsto \boxed{= 14}

4 0
2 years ago
Gary drove to the park at a rate of 50 miles per hour if it took him 2.5 hours to get from his house to the park how far away is
Marina86 [1]

Answer:

The distance of the park from the Gary's house is 125 miles.

Step-by-step explanation:

Speed of Gary = 50 miles/hour

Time taken by Gary to reach the park from his house = 2.5 hours

Now, we know that,

Distance travelled = speed × time

So,  distance between park and Gary's house = speed × time

= 50 × 2.5

= 125 miles

So, the park is 125 miles away from the Gary's house.

4 0
3 years ago
A simple random sample of size n from a finite population of size N is a sample selected such that each possible sample of size
Bezzdna [24]

Answer:

a) has the same probability of being selected

Step-by-step explanation:

A simple random sampling means that each possible sample of size n has the same probability of being selected.

Then your answer is:

a) has the same probability of being selected

8 0
3 years ago
Factor the expression below.4x2 - 1
marusya05 [52]

Answer:

C. (2x – 1)(2x + 1)

Step-by-step explanation:

4x² – 1 = (2x)(2x) – 1 = (2x – 1)(2x + 1)

5 0
3 years ago
Read 2 more answers
What is the area of the region bounded between the curves y=x and y=sqrt(x)?
erastova [34]

Answer:

\frac{1}{6}

Step-by-step explanation:

y = x     .....(1)

y=\sqrt{x}     .... (2)

By solving equation (1) and equation (2)

x = \sqrt{x}

\sqrt{x}\left ( \sqrt{x}-1 \right )=0

\sqrt{x}=0 or \left ( \sqrt{x}-1 \right )=0

x = 0, x = 1

y = 0, y = 1

A = \int_{0}^{1}ydx(curve)-\int_{0}^{1}ydx(line)

A = \int_{0}^{1}\sqrt{x}dx-\int_{0}^{1}xdx

A = \frac{2}{3}[x^\frac{3}{2}]_{0}^{1}-\frac{1}{2}[x^2]_{0}^{1}

A = \frac{2}{3}-\frac{1}{2}

A = \frac{1}{6}

8 0
3 years ago
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