A) <span>3x+5y-x+2y=
</span><span>Group the same sexes
3x-x+5y+2y=
3x-x=2x
+5y+2y=7y
answer: 2x+7
</span>
<span>B) 3g+5h+4g-2h=
</span><span>Group the same sexes
3g+4g+5h-2h=
3g+4g=7g
+5h-2h=+3h
</span><span>answer: 7g+3h
</span>
<span>C) 4p+2p-3p=
</span>Do not need to be grouped. Because everyone is of a gender
4p+2p=6p
6p-3p=3p
<span>answer: 3p
</span>D) 9s-5s+2s-s=
Do not need to be grouped. Because everyone is of a gender
9s-5s=4s
4s+2s=6s
6s-s=5s
<span>answer: 5s
</span>
<span>E) 8t+3r-7t-9r=
</span><span>Group the same sexes
8t-7t+3r-9r=
8t-7t=t
+3r-9r=-3r
</span><span>answer: t-3r</span>
Answer:
x = 57
Step-by-step explanation:
Hope this helps :)
Answer:
x-70
Step-by-step explanation:
The three vectors 
, 
, and 
each terminate on the plane. We can get two vectors that lie on the plane itself (or rather, point in the same direction as vectors that do lie on the plane) by taking the vector difference of any two of these. For instance,
Then the cross product of these two results is normal to the plane:
Let 
be a point on the plane. Then the vector connecting to a known point on the plane, say (0, 0, 1), is orthogonal to the normal vector above, so that
which reduces to the equation of the plane,
Let 
. Then the volume of the region above 
and below the plane is
Answer:
0.546 , -4.71
Step-by-step explanation:
Given:
An angle's initial ray points in the 3-o'clock direction and its terminal ray rotates counter -clock wise.
Here, Slope = tan\theta
If θ = 0.5
Then, Slope = tan(θ) = tan(0.5) = 0.546
If θ = 1.78
Then, Slope = tan(θ) = tan(1.78) = - 4.71
The expression (in terms of θ) that represents the varying slope of the terminal ray.
Slope = m = tanθ, where θ is the varying angle
