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3 years ago

How is the interquartile range calculated? HELP WITH APEX PLEASE!

Mathematics

2 answers:

AfilCa [17]3 years ago

8 0

By definition the interquartile range or IQR is obtained when the 25th percentile or $Q_{1}$ is subtracted from the 75th percentile or $Q_{3}$ .

Thus, from the above definition, the formula for IQR is:

$IQR=Q_{3}-Q_{1}$

As we can see from the provided options that the definition of IQR matches the expression provided in Option A and thus, Option A is the correct answer.

Viktor [21]3 years ago

3 0

Quartile 3 (Q3) minus quartile 1 (Q1) is right for apex.

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Solve the following system of equations for a and for b:

viktelen [127]

Answer:

$a=3\\b=1$

Step-by-step explanation:

$9a+3b=30\\8a+4b=28$

Let's solve the second equation for a to later on replace it in the first equation.

$8a+4b=28\\8a=28-4b\\a=\frac{28-4b}{8}$

Now plug this into the first equation.

$9a+3b=30\\9(\frac{28-4b}{8})+3b=30$

Distribute the 9

$(\frac{252-36b}{8}) +3b=30$

Break down the fraction.

$\frac{252}{8}-\frac{36b}{8}+3b=30$

Simplify.

$\frac{63}{2}-\frac{9}{2}b+3b=30$

Subtract $\frac{63}{2}$

$-\frac{9}{2}b+3b=30-\frac{63}{2}$

Combine like terms.

$\frac{-9+2*3}{2}b=\frac{30*2-63}{2}$

$\frac{-9+6}{2}b=\frac{60-63}{2}$

$\frac{-3}{2}b=\frac{-3}{2}$

Muliply by the reciprocal or inverted fraction next to b.

$(-\frac{2}{3})(-\frac{3}{2}) b=-\frac{3}{2}(-\frac{2}{3})$

$b=1$

Now plug this value into any of the equations to find the value of a.

$8a+4b=28\\8a+4(1)=28\\8a+4=28\\8a=28-4\\8a=24\\a=\frac{24}{8}\\ a=3$

5 0

3 years ago

PLEASE HELP! 20 POINTS

OLEGan [10]

Answer:

1,215 i think please be right

7 0

2 years ago

A fish starts swimming at -50m and increases 13m. Which equation best represents the situation and the fish's final elevation? a

marta [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

Evaluate the expression ab for a = 10 and b = 4.

xz_007 [3.2K]

A x B

= 10 x 4

= 40

Therefore answer is 40

7 0

3 years ago

Read 2 more answers

What is the answer to A and B?

Alex_Xolod [135]

For A) u must start at -3 on y lines. Then move points up 1 and 3 to the right. Makes point and continue to make lines
For B) start at 5 on y lines, and remember -x is same thing is -1. And negative means go down! So move 1 down and 1 to the right and make point then move 1 down and make 1 right and make second points and continue. Draw a lines.

The solution is when u see two lines from two equations crosses to each other. There’s solution shown.

3 0

3 years ago