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3 years ago

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How do you plot a inequality

1 answer:

Dahasolnce [82]3 years ago

7 0

Would appreciate your sharing actual inequalities to graph. Otherwise the topic is a bit broad.

Supposing you wanted to graph the inequality x<5:

Draw a dashed line through x=5, and then shade the area to the left of this line.

Supposing you wanted to graph the inequality x less than or equal to 5:

Draw a solid line through x=5, and then shade the area to the left of this line.

Please, respond with an inequality that you want to graph, and I'll help you with it.

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Help plz someone help me plz ty

MrRa [10]

Answer: 18.75 for each girl

Step-by-step explanation:

First you take the unit rate 2.50 multiply by 5.

2.50 x 5 = 12.50

12.50 x 3 = 37.50

37.50 / 2 = 18.75

7 0

3 years ago

For every 5 coins carmen gets ,she gives 2 to her brother Frankie.If carmen has 9 coins,howmany coins does Frankie have?

FrozenT [24]

Answer:

Frankie have 6 coins

Step-by-step explanation:

For every 5 coins Carmen gets ,she gives 2 to her brother Frankie

Out of 5 coins, Carmen given 2 to her brother Frankie

So Carmen has 3 coins and Frankie has 2 coins

Ratio of coins , Frankie to Carmen is

2: 3

We need to find the number of coins Frankie has if Carmen has 9 coins

ratio of Frankie to Carmen is x : 9

Now make a proportion and solve for x

$\frac{2}{3} =\frac{x}{9}$

Cross multiply it

2*9 = 3*x

18 = 3x

Now divide both sides by 3

so x= 6

Frankie have 6 coins

7 0

3 years ago

----------- are used to represent an unknown quantity in a mathematical expression.

anastassius [24]

A letter or symbol is used to represent an unknown quantity

4 0

2 years ago

Read 2 more answers

How many solutions exist for the mixed-degree system graphed below?

Likurg_2 [28]

The answer is one solution. Hope this helps

8 0

2 years ago

Read 2 more answers

The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand

Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

$P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})$

$P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})$

$P(X > 1560) = P(Z > \dfrac{110}{220})$

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean $\mu_x$ = np = 52 × 0.3085 = 16.042

The standard deviation = $\sqrt {n \time p (1-p)}$

The standard deviation = $\sqrt {52 \times 0.3085 (1-0.3085)}$

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

$Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})$

$Pr ( Y > 20) = P(Z >1 .338)$

From z tables

P(Y > 20) $\simeq$ 0.0903

7 0

3 years ago