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PtichkaEL [24]
3 years ago
11

NEED HELP PLEASE ANSWER

Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0

descending is negative

250 -16t  

h(t) = 250-16t

Choice B is the same

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Two number add to 336 and the first is bigger that the second. What are the two numbers?
makvit [3.9K]
336 divided by 2 is 168.

so just change it up. 

the two numbers can be 166+170


7 0
3 years ago
The difference of Mai's age and 12 is 60
Fynjy0 [20]

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5 0
3 years ago
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Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
4 years ago
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Sav [38]

Answer:

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30(116)

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Divide this amount by 439 to find how many laptops they can buy:

3020/439

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Round down to 6 since you can only have full laptops:

= 6

So, they can buy 6 laptops

6 0
3 years ago
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rodikova [14]
The answer has to 2.26 because 2.26 is bigger than 2.25
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3 years ago
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