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Vlada [557]
3 years ago
8

Wendy described four triangles as shown below: Triangle A: All sides have length 9 cm. Triangle B: Two sides have length 10 cm,

and the included angle measures 60°. Triangle C: Two angles measure 50°. Triangle D: Base has length 8 cm, and base angles measure 45°. Which triangle is not a unique triangle? Triangle A Triangle B Triangle C Triangle D
Mathematics
1 answer:
liq [111]3 years ago
7 0

Answer:

Triangle C

Step-by-step explanation:

Triangle A: All sides have length 9 cm.

<em>By </em><em>SSS</em><em> this is a </em><em>unique</em><em> triangle. </em>

Triangle B: Two sides have length 10 cm, and the included angle measures 60°.

<em>By </em><em>SAS</em><em> this is a </em><em>unique</em><em> triangle. </em>

 

Triangle C: Two angles measure 50°.

<em>This gives us at most </em><em>SS Similarity</em><em>, so we do not have a unique triangle. The triangle sides can be any length. </em><em>This is not unique</em><em>. </em>

<em> </em>

Triangle D: Base has length 8 cm, and base angles measure 45°. Which triangle is not a unique triangle?

<em> This gives us </em><em>ASA</em><em>, so we have a </em><em>unique</em><em> triangle. </em>

Answer: Triangle C

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A rare first-edition book is currently priced at $200. After one year, the price of the book is anticipated to be 1.15 times the
Yakvenalex [24]

Answer:

Graph Y is the correct answer

Step-by-step explanation:

after 1 year, the price would be $200 * 1.15 = $230

After 2 years, the price would be $230 * 1.25 = $264.5

As you can see, the graph X and Z do not start at $200 in the first year so it will be eliminated

The graph W show that after 2 years the price is $300 but the second year must have the price of $264.5 so the only option left is graph Y.

Hope this can help!

4 0
3 years ago
NEED HELP
Zina [86]

Answer:

\displaystyle \frac{1}{2}(x^3-2x^2-5x+6)

Step-by-step explanation:

<u>Polynomials </u>

a)

The polynomial whose graph is shown is of third degree because it has three real roots. The roots of a polynomial are the values of x that make the expression equal to zero. We can see it happens three times in the graph provided. The roots or zeros are  

x=-2, x=1, x=3

b)

The factored form of a polynomial whose roots x_1, x_2, x_3 are known is

a(x-x_1)(x-x_2)(x-x_3)

We know the value of the roots, thus the polynomial is written as

a(x+2)(x-1)(x-3)

We need to find the value of a. We do that by replacing the value of x=0 and finding a that makes f(0)=3 (as seen in the graph). Thus

a(0+2)(0-1)(0-3)=3

a(2)(-1)(-3)=3

a(6)=3

\displaystyle a=\frac{3}{6}

\displaystyle a=\frac{1}{2}

Thus the factored form of the polynomial is

\displaystyle \frac{1}{2}(x+2)(x-1)(x-3)

c)

Let's multiply all the factors

\displaystyle \frac{1}{2}(x+2)(x-1)(x-3)

\displaystyle \frac{1}{2}(x^2+2x-x-2)(x-3)

\displaystyle \frac{1}{2}(x^2+x-2)(x-3)

\displaystyle \frac{1}{2}(x^3-3x^2+x^2-3x-2x+6)

\boxed{ \displaystyle \frac{1}{2}(x^3-2x^2-5x+6)}

7 0
4 years ago
I need help! Please answer this question
Effectus [21]
The answer is : 12 ok ?
3 0
3 years ago
Read 2 more answers
At the Yogurt Pump, all flavors of frozen yogurt are $1.75 per scoop. If a customer buys v vanilla scoops and c chocolate scoops
Elza [17]
The answer is going to be D
5 0
3 years ago
Let f be a continuous function defined on the interval [0,1] such that f(0) = f(1). Show that there exists a number 0 &lt;= a &l
Leni [432]

Explanation:

In order to prove that affirmation, we define the function g over the interval [0, 1/2] with the formula g(x) = f(x+1/2)-f(x) .

If we evaluate g at the  endpoints we have

g(0) = f(1/2)-f(0) = f(1/2) - f(1) (because f(0) = f(1))  

g(1/2) = f(1) - f(1/2) = -g(0)

Since g(1/2) = -g(0), we have one chance out of three

  • g(0) > 0 and g(1/2) < 0
  • g(0) < 0 and g(1/2) > 0
  • g(0) = g(1/2) = 0

We will prove that g has a zero on [0,1/2]. If g(0) = 0, then it is trivial. If g(0) ≠ 0, then we are in one of the first two cases, and therefore g(0) * g(1/2) < 0. Since f is continuous, so is g. Bolzano's Theorem assures that there exists c in (0,1/2) such that g(c) = 0.  This proves that g has at least one zero on [0,1/2].

Let c be a 0 of g, then we have

0 = g(c) = f(c+1/2)-f(c)

Hence, f(c+1/2) = f(c) as we wanted.

5 0
3 years ago
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