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Sidana [21]
3 years ago
14

A​ $100 deposit today that earns an annual interest rate of​ 10% is worth how much at the end of two​ years? assume all interest

received at the end of the first year is reinvested the second year.
a. ​$121
Business
1 answer:
Alexxx [7]3 years ago
6 0
Fv=100×(1+0.1)^(2)=121
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The difference between the monthly payment of R and S is equal to $48.53 by following the compound interest formula. Thus, Loan R's monthly loan amount is greater than Loan S.

<h3>What is a Compound interest loan?</h3>

Combined interest (or compound interest) is the loan interest or deposit calculated based on both the original interest and accrued interest from earlier periods.

\rm\,For\,R\\\\P = \$\,17,550\\r\,= 5.32\%\\Time\,= n= 7\,years\\Amount\,paid= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\=[ 17,550 (1+\dfrac{5.32}{100\times12})^{7\times12} ]\\= [ 17,550 (\dfrac{12.0532}{12})^{84} ]\\\\=  [ 17,550 (1.00443^{84} ]\\\\= \$ 25,440.48\\\\Total\,monthly\,payment = \rm\,\dfrac{25,440.48}{84}\\\\= \$\, $302.86\\\\

\rm\,For\,S =\\\\P=\,\$ 15,925\\r\,= 6.07\%\\T=n= 9\,years\\\\Amount\,paid\,= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\\\\= [15,925(1+\dfrac{0.0607}{12})^{9\times12} ]\\\\\\= [15,925(1+\dfrac{0.0607}{12})^{108} ]\\\\=[15,925(1.7247.84)} ]\\\\\= \$27,467.19\\\\Total\,monthly\,payment =\dfrac{\rm\,\$\,27,469.19}{108}\\\\= \$ 254.326\\\\

The difference between the monthly payment of R and S is equal to $48.53.

Hence, Loan R's monthly payment is greater than the loan's monthly payment by $48.53

To learn more about Compound interest, refer to the link:

brainly.com/question/14331235

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