If you have 20 coins worth $1.35, and you only have nickels and dimes, how many do you have of each coin?
1 answer:
N + d = 20....n = 20 - d
0.05n + 0.10d = 1.35
0.05(20 - d) + 0.10n = 1.35
1 - 0.05d + 0.10d = 1.35
-0.05d + 0.10d = 1.35 - 1
0.05d = 0.35
d = 0.35/0.05
d = 7 <==== 7 dimes
n + d = 20
n + 7 = 20
n = 20 - 7
n = 13 <=== 13 nickels
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