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3 years ago

If you have 20 coins worth $1.35, and you only have nickels and dimes, how many do you have of each coin?

1 answer:

5 0

N + d = 20....n = 20 - d
0.05n + 0.10d = 1.35

0.05(20 - d) + 0.10n = 1.35
1 - 0.05d + 0.10d = 1.35
-0.05d + 0.10d = 1.35 - 1
0.05d = 0.35
d = 0.35/0.05
d = 7 <==== 7 dimes

n + d = 20
n + 7 = 20
n = 20 - 7
n = 13 <=== 13 nickels

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Answer: The girls walked $1\dfrac38$ miles.

Step-by-step explanation:

Given: Distance from home to school = $\dfrac{6}{10}$ mile

Distance from school to store = $\dfrac38$ mile

Distance from store to home = $\dfrac25$ miles

Total distance = $\dfrac6{10}+\dfrac38+\dfrac25$

= $\dfrac{6\times4+3\times5+2\times8}{40}$ [L.C.M.(10,8,5)=40]

= $\dfrac{24+15+16}{40}$

= $\dfrac{55}{40}$

= $\dfrac{11}{8}=1\dfrac38$ miles

Hence, The girls walked $1\dfrac38$ miles.

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3 years ago

How much is 5a(6b+12)

andreev551 [17]

When writing an expression in expanded form, we just need to multiply what's outside the parentheses by everything that is inside the parentheses.

5a (6b + 12)

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And that is our answer.
5a (6b + 12) in expanded form is 30ab + 60a.
Hope that helped =)

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3 years ago

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if you roll a fair six-sided number cube twice. what is the probability that the first roll is a 5 and the second is a 6?

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3 years ago

. Suppose that the times required for a cable company to fix cable problems in its customers' homes are uniformly distributed be

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The probability that a randomly selected cable repair visit will take at least 43 minutes will be 88%.

Given: The times required for a cable company to fix cable problems in its customers' homes are uniformly distributed between 40 minutes and 65 minutes.

It can be deduced that the probability that a randomly selected cable repair visit will take at least 43 minutes will be calculated thus:

= 1 - [(43 - 40)/(65 - 40)

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Hence, The probability that a randomly selected cable repair visit will take at least 43 minutes will be 88%.

Learn more about probability here brainly.com/question/6354635

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1 year ago