Answer:
1/64
Explanation:
<em>The probability of the offspring being homozygous dominant for the three alleles is 1/64.</em>
Since the three characters assort independently, the probability of the offspring being homozygous dominant for all the three traits is an independent event.
For independent events, the probability of all the events happening together is the multiplication of individual event's probability.
For a cross involving two heterozygotes, taking tall/dwarf for example:
Tt x Tt = TT, 2Tt, tt
The probability of obtaining a homozygous dominant genotype is 1/4.
Hence, the probability of the offspring being homozygous dominant for the three alleles will be:
1/4 x 1/4 x 1/4 = 1/64
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