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kap26 [50]
3 years ago
5

Which group is incorrectly paired with its description?

Biology
1 answer:
marta [7]3 years ago
8 0

Answer:

b. red algae—eukaryotes that acquired plastids by secondary endosymbiosis

Explanation:

  • <em>Red algae did not acquire plastids by secondary endosymbiosis and thus, option b is an incorrect pair. </em>
  • Red algae are eukaryotes that are red in the color not because they acquired plastids y endosymbiosis but because they produce the enzyme phycoerythrin and phycocyanin which masks the other pigments present in it.
  • Secondary endosymbiosis is a process by which the product of primary endosymbiosis is engulfed by another organism. Such type of process never occurred in case of red algae.
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Explanation:

Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.

In contrast to this, her husband is diseased so his genotype will be XᵇY.

The Punnett square diagram related to the cross is attached.

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They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.

(b) If the husband were G6PD deficient, the answer will not change.

The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.  

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