Answer:
Yes
Step-by-step explanation:
When graphing it you can see that (3, 4) is clearly a solution. The proper equation using slope intercept form is y= 2/3x + 2.
C^2-64 is a square roots factoring one. you take the square root of c^2 which is c and then the square root of 64 which is 8 or -8 so the answer is (c-8)(c+8). and it is a special product
Answer:
a. h = 60t − 4.9t²
b. 12.2 seconds
c. 183.7 meters
Step-by-step explanation:
a. Given:
y₀ = 0 m
v₀ = 60 m/s
a = -9.8 m/s²
y = y₀ + v₀ t + ½ at²
h = 0 m + (60 m/s) t + ½ (-9.8 m/s²) t²
h = 60t − 4.9t²
b. When the ball lands, h = 0.
0 = 60t − 4.9t²
0 = t (60 − 4.9t)
t = 0 or 12.2
The ball lands after 12.2 seconds.
c. The maximum height is at the vertex of the parabola.
t = -b / (2a)
t = -60 / (2 × -4.9)
t = 6.1 seconds
Alternatively, the maximum height is reached at half the time it takes to land.
t = 12.2 / 2
t = 6.1 seconds
After 6.1 seconds, the height reached is:
h = 60 (6.1) − 4.9 (6.1)²
h = 183.7 meters
Answer:
22 students
Step-by-step explanation:
218 students - 20 students = 198 students on buses
198 students / 9 buses = 22 students per bus
yeah i guess you re right sorry for making confusion
