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2 years ago

What is the area of the following 2D figure? Assume a = 7 ft., b = 5 ft., and c = 9 ft. a b C

Mathematics

1 answer:

Komok [63]2 years ago

3 0

The area of the 2-D figure = area of trapezoid + area of rectangle = 85 ft.².

<h3>What is the Area of a 2D-Figure?</h3>

The area of the 2-D figure that is shown is, A = 1/2(a + c)b + (b)(c).

Given the following:

a = 7 ft.
b = 5 ft.
c = 9 ft.

Plug in the values:

Area = 1/2(7 + 9)5 + (5)(9)

Area = 85 ft.²

Learn more about area of 2-D figure on:

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Drag each object to show whether cost is proportional to area in the situation represented.

Elodia [21]

Answer:

see the explanation

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

<u><em>Verify each case</em></u>

case 1) Sod that is quoted at a set price per square yard plus a labor fee

The Cost is NOT proportional to Area, because the line don't pass though the origin (the equation has an y-intercept equal to the labor fee)

case 2) Pavers that cost a set amount per square foot

The Cost is Proportional to Area

In this problem the constant of proportionality k is equal to the set amount per square feet

case 3) Hardwood flooring that cost $16 for every 2 square feet

The Cost is Proportional to Area

The constant of proportionality k is equal to

$k=\frac{y}{x}$ ----> $k=\frac{16}{2}=\$8\ per square\ foot$

The linear equation is $y=8x$

case 4) The given graph

Is a line that passes though the origin

The Cost is Proportional to Area

case 5) The given table

Find the constant of proportionality k for each ordered pair

If all values of k are the same, then the cost is proportional to area

For x=2, y=3,000 -> $k=\frac{y}{x}$ --> $k=\frac{3,000}{2}=1,500$

For x=4, y=4,000 -> $k=\frac{y}{x}$ --> $k=\frac{4,000}{4}=1,000$

For x=6, y=6,000 -> $k=\frac{y}{x}$ --> $k=\frac{6,000}{6}=1,000$

the values of k are different

therefore

The Cost is NOT proportional to Area

case 6) A concrete patio quoted at a bulk cost for 50 square feet

Not enough information

8 0

3 years ago

Please help me would be very appreciated.

maria [59]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The number of hits on a website doubles every month. About 10,600 people visited the website during May. The expression 10,600 ·

Ivanshal [37]

Answer:

The correct option is;

B. 10,600; 2,650; About 10,600 people visited the website in May. About 2,650 people visited the website in March

Step-by-step explanation:

The given parameters are;

The number of people that visit the website every month = 2 × The number of people that visited the website the previous month

The number of people that visit the website during May ≈ 10,600

The number of visitors of the website are given by the expression 10,600 × $2^t$

For t = 0, we have;

The number of visitors of the website = 10,600 × 2⁰ = 10,600

For t = -2, we have;

The number of visitors of the website = 10,600 × 2⁻² = 2,650

Therefore, the website had about 10,650 visitors in May and about 2,650 visitors in 2 months earlier in March.

3 0

3 years ago

If I have 3 integers that are greater than -5, and less than or equal to 3. The median is -1, no Mode and range is 5, the mean i

Fudgin [204]

Answer:

{-2, -1 , 3}

Step-by-step explanation:

When we have a set like:

{x₁, x₂, x₃}

The mode is the value that appears the most, so if there is no mode, then each value appears just one time.

The median is the middle value, here we know that the median is -1, then we can rewrite the set as:

{x₁, -1 , x₃}

The mean is computed as:

Mean = (x₁ + x₂ + x₃)/3

in this case we know that the mean is 0, then:

0 = (x₁ + x₂ + x₃)/3

then the numerator must be zero, so:

0 = (x₁ + x₂ + x₃)

replacing the value of x₂ = -1 we get:

0 = (x₁ - 1 + x₃)

where:

-5 < x₁ < -1 < x₃ ≤ 3

Now we can select the values of x₁ and x₃ such that the sum is equal to zero, and it meets the wanted restrictions.

here we can choose x₃ to be equal to 3 (the maximum allowed value), I do this because I noticed that the other values that are larger than -1 will not work (just with quick math).

then:

0 = x₁ - 1 + 3

Now we can solve this for x₁

0 = x₁ + 2

-2 = x₁

Then the set is:

{-2, -1 , 3}

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3 years ago

Solve y = mx + b for x

eimsori [14]

Y=mx+b
-b -b
--------------
-by= mx
-------------
m m

-by
------
m

8 0

3 years ago

What is the area of the following 2D figure? Assume a = 7 ft., b = 5 ft., and c = 9 ft. a b C​

What is the area of the following 2D figure? Assume a = 7 ft., b = 5 ft., and c = 9 ft. a b C