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Strike441 [17]
3 years ago
6

A merchant has 120 litres and 180 litres of two kinds of oil. He wants to sell the oil by filing the two kinds of equal volumes.

Find the greatest volume of such a tin.
Mathematics
1 answer:
ANEK [815]3 years ago
3 0

Answer:

HCF of 120 and 180 is 60 and hence a measuring tin of 60 litre volume should be bought.

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polet [3.4K]

Answer:

B

Step-by-step explanation:

From the statement, we are given a function that shows the number of cell tower users f(x) after x years, from the year 2010 to 2019, so, to solve the problem, we need to remember that the domain is equal to all the values that the variable (x for this case) could take making the function itself exist.

So, the given function is a function of years, and we know that "x" represents the years from 2010 (starting value), to 2019 (ending value) meaning that the domain is located between those two values.

Hence, the correct option is:

B. 0 ≤ x ≤ 5,000

3 0
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Rina8888 [55]
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Answer:

(3,-4)

Step-by-step explanation:

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Use trig to find the legs of ABC if the base is AC and the height is BC (round to nearest tenth)​
umka2103 [35]

Answer:

<u>GIVEN :-</u>

  • ∠A = 15°
  • Length of AB (hypotenuse) = 60 ft

<u>TO FIND :-</u>

  • Length of BC
  • Length of AC
  • Area of ΔABC

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}

<u>SOLUTION :-</u>

In ΔABC ,

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=> 0.2588... = \frac{BC}{60}

=> BC = (0.2588....) \times 60 = 15.5291..... ≈ 15.5 ft

  • \cos 15 = \frac{AC}{60}

=> 0.9659..... = \frac{AC}{60}

=> AC = (0.9659.....) \times 60 = 57.9555..... ≈ 58 ft

Area of ΔABC = \frac{1}{2} \times 58 \times 15.5 = 449.5 \:ft^2

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2 years ago
What is the x-intercept of the line with this equation −5x+1/5y=15 ?
bulgar [2K]

9

Step-by-step explanation:

I don't no but 5 and 1 is 6 so add 9 more and you have 15

6 0
3 years ago
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