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3 years ago

HELP I NEED HELP SOLVING THIS PROBLEM AN EXPLAIN IT TO ME PLZ?

Mathematics

1 answer:

Sophie [7]3 years ago

5 0

Check on slader.com it will show you the answer if you enter the textbook name

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Can someone pls help

UNO [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

12a+6b equivalent expression

patriot [66]

Answer:

$6(2a+b)$

Step-by-step explanation:

The given expression is

$12a+6b$

To find the equivalent expression of the given one, we just have to factor.

In this case, the only thing we can do to rewrite is to extract the common greatest factor, which is 6

$12a+6b\\6(2a+b)$

Therefore, the equivalent expression is

$6(2a+b)$

5 0

3 years ago

Which ones apply?<br> Answers please

Artyom0805 [142]

Options 1 and 3 are the correct answers

6 0

3 years ago

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

4 0

2 years ago

3(x+1)=5(x−2)+7<br> solve for x

bearhunter [10]

X=3

3(3+1)=12

5(3-2)+7=12

8 0

2 years ago