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elena-14-01-66 [18.8K]
3 years ago
6

5. Express the product as a polynomial in simplest form: (x + 5)(x - 5)(2x + 3)

Mathematics
1 answer:
Tasya [4]3 years ago
5 0

Answer:

2x^3+3x^2-50x-75

Step-by-step explanation:

(x+5)(x-5)=x^2-25

(x^2-25)(2x+3)=2x^3+3x^2-50x-75

Can I have brainliest!

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Simplify the expression (6+2)^2-4×3 using the order of operations((the 2 is an exponent))
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Two motorcyclist A and B, started simultaneously moving towards each other. From the graph given below, find the distance each o
harina [27]

Answer:

<em>Distance covered by motorcyclist A = 700 - 300 = 400 km</em>

<em>Distance covered by motorcyclist B = 300 - 0 = 300 km</em>

<em>The time before they met went for 5 hours</em>

<em>Average speed of motorcyclist A would be: 400/5 = 80 km/hour</em>

<em>Average speed of motorcyclist B would be : 300/5 = 60 km/hour</em>

Step-by-step explanation:

<u><em>In the given question first we have to find the distance covered by each of them.</em></u>

Look at the graph. Motorcyclist A started from 700 km and met at 300 km with motorcyclist B

Thus the distance covered by motorcyclist A = 700 - 300 = 400 km

Motorcyclist B started from 0 km and met with A at point 300 km.

Thus the distance covered by motorcyclist B = 300 - 0 = 300 km

<u><em>Now we have to find the time before they meet.</em></u>

Look at the graph. Both motorcyclists met at point t=5

Thus the time before they met went for 5 hours

<u><em>Now find out the average speed of motorcyclists</em></u>

To find the average speed we require total distance and time.

Motorcyclist A covered 400 km within 5 hours

<em>Average speed of motorcyclist A would be: 400/5 = 80 km/hour</em>

<em>Average speed of motorcyclist B would be : 300/5 = 60 km/hour</em>

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8 0
3 years ago
How many minutes does Ali run per calorie burned?<br><br> What is the slope of the graph?
schepotkina [342]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Help me out please?<br>chapter : exponents and powers​
belka [17]

Answer:

\frac{125}{27}

Step-by-step explanation:

\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}

Lets expand all the composite numbers into prime numbers.

=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}

Lets cancel 2^{-4} from numerator and denominator.

=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}

Using laws of exponents , lets solve this.

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=> 3^{-3} \times 5^{[1 - (-2)]}

=> 3^{-3} \times 5^{3}

=> \frac{5^3}{3^3} = \frac{125}{27}

4 0
3 years ago
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