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miskamm [114]
4 years ago
14

12 23 17 20 14 14 18 16 17 18 18 mean median mode round to the rarest tenth

Mathematics
2 answers:
Vaselesa [24]4 years ago
3 0
The mean is the average. To find this, we add up all the numbers, then divide by the number of numbers there are.
12+23+17+20+14+14+18+16+17+18+18= 187
187/11=17
The mean is 17.

The median is the middle number. To find this, line up all the numbers, smallest to largest.
12, 14, 14, 16, 17, 17, 18, 18, 18, 20, 23
You then cross off numbers from both sides, until you have 1 number remaining.
Your median is 17.

The mode is the number that occurs most frequently.
Your mode is 18.

andreev551 [17]4 years ago
3 0
The median is the middle number of a list of numbers from least to greatest.
I will set up the numbers from least to greatest for you.
12, 14, 14, 16, 17, 17, 18, 18, 18, 20, 23.
To determine a fun way to find the median, cross out the smallest number with the largest number until you can no longer do so.
12, 14, 14, 16,17, 17, 18, 18, 18, 20, 23.
14, 14, 16 ,17, 17, 18, 18, 18, 20.
14, 16, 17, 17, 18, 18, 18.
16, 17, 17, 18, 18.
17, 17, 18.
17.
Your median is 17.
The mode is the number that appears the most within the list of numbers. If we look back from our list of numbers from least to greatest, 18 appears the most.
Your mode is 18.
The mean is the average, in which the sum of all numbers is divided by how many numbers there are.
The sum of the numbers is 187. We have 11 numbers total.
Divide the sum by how many numbers we have in total for the average (mean).
187/11 = 17.
Your mean is 17.
I hope this helps!
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Read 2 more answers
Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc
Lelechka [254]

Answer:

a)

P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}

For any integer k between 0 and 15, and 0 for other values of k.

b)

P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865

c) P(6 ≤ X ≤ 10) = 0.2737

d)  μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

a)

P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}

For any integer k between 0 and 15, and 0 for other values of k.

b)

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252

P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252

P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559

P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668

P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134

Thus,

P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034

P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131

P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393

P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918

P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652

Thereofre,

P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737

d)  μ = n*p =  15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

3 0
3 years ago
Giving away extra points​
Eva8 [605]
Hi ty for the points, answer is the light blue one
7 0
3 years ago
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