Question

Cd has an endpoint at (2, -1) and a midpoint at (8, 3). which measure is closest to the length of cd

Answer 1

Answer:

4$\sqrt{13}$

Step-by-step explanation:

The length of CD will be twice the distance from the midpoint to the endpoint

To calculate the length use the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (2, - 1) and (x₂, y₂ ) = (8, 3)

d = 2 × $\sqrt{(8-2)^2+(3+1)^2}$

  = 2 × $\sqrt{6^2+4^2}$

  = 2 × $\sqrt{52}$

  = 2 × $\sqrt{4(13)}$

  = 2 × 2$\sqrt{13}$ = 4$\sqrt{13}$ ← exact length