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Nookie1986 [14]
4 years ago
9

Mark is gluing a ribbon around the sides of a picture frame. The frame is 11 inches long and 7 inches wide. How much ribbon does

mark need?
Mathematics
2 answers:
zalisa [80]4 years ago
8 0
You are looking for the perimeter, so you need to add 11+11+7+7. That equals 36.
zaharov [31]4 years ago
3 0
You need to know the perimeter or this because he want to wrap the ribbon around the frame. 11(2)+7(2)= 22+14 36 Mark needs 36 inches of ribbon.
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Write an equation in point-slope form for the line that passes through the point with the given slope. (-5, -8), m = -2
Arada [10]

Answer:

Y= -2x - 18

Step-by-step explanation:

Hope it works

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3 years ago
A single card is drawn from a standard 52 card deck. Work out the probability of choosing "an ace". Give your answer in its simp
Furkat [3]

Answer:

1/13

Step-by-step explanation:

Total cards = 52

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Probability = 4/52 = 1/13

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2 years ago
Explain the different ways it is possible to add two rational numbers and get a negative number.
Eduardwww [97]

<u>Answer:</u>

both numbers are negative

negative number is greater than the positive number

<u>Step-by-step explanation:</u>

In order to add two rational numbers and get a negative value, one of two scenarios should occur:

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3 years ago
What should be completed first when simplifying 2(x - 3) + 6(4x + 1)?
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parantheses

Step-by-step explanation:

6 0
3 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
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