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3 years ago

15

Which polynomial is in standard form?

2 answers:

skelet666 [1.2K]3 years ago

7 0

Answer:

A.

Step-by-step explanation:

Alchen [17]3 years ago

7 0

<h2><em>D 2x^3+4x^2-7x+5</em></h2><h2><em>this is</em></h2>

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LA plane is trying to travel 250 miles at a bearing of 20° E of S, however, it ends 230 miles away from the

Semmy [17]

Answer:

The wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ East of North with respect to the destination point.

Step-by-step explanation:

Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the starting point in the direction of 35° E of South as shown in the figure.

So, we have |OD|=250 miles and |OD'|=230 miles.

Vector $\overrightarrow{DD'}$ is the displacement vector of the plane pushed by the wind.

From figure, the magnitude of the required displacement vector is

$|DD'|=\sqrt{|AB|^2+|PQ|^2}\;\cdots(i)$

and the direction is $\alpha$ east of north as shown in the figure,

$\tan \alpha=\frac{|PQ|}{|AB|}\;\cdots(ii)$

From the figure,

$|AB|=|OA-OB|$

$\Rightarrow |AB|=|OD\cos 20 ^{\circ}-OD'\cos 35 ^{\circ}|$

$\Rightarrow |AB|=|250\cos 20 ^{\circ}-230\cos 35 ^{\circ}|$

$\Rightarrow |AB|=45.52$ miles

Again, $|PQ|=|OP-OQ|$

$\Rightarrow |PQ|=|OD\sin 20 ^{\circ}-OD'\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=|250\sin 20 ^{\circ}-230\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=46.42$ miles

Now, from equations (i) and (ii), we have

$|DD'|=\sqrt{|45.52|^2+|46.42|^2}=65.01$ miles, and

$\tan \alpha=\frac{|46.42|}{|45.52|}$

$\alpha=\tan^{-1}\left(\frac{|46.42|}{|45.52|}\right)=45.56 ^{\circ}$

Hence, the wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ E astof North with respect to the destination point.

5 0

3 years ago

Please Help! GEOMETRY!

lara31 [8.8K]

I think the answer should be A n goodluck

3 0

4 years ago

Read 2 more answers

8(y+4)=7y+38 asap pls

Readme [11.4K]

Distribute
remember a(b+c)=ab+ac
8(y+4)=8(y)+8(4)=8y+32

8y+32=7y+38
minus 7y both sides
y+32=38
mius 32 oth sides
y=6

8 0

3 years ago

A spherical ball has a diameter of 8 inches. The ball has a slow leak in which the air escapes at the rate of 2.5 inches per sec

s344n2d4d5 [400]

Answer:

107.2 seconds

Step-by-step explanation:

Step one:

given

the diameter of ball 8 inches

radius= 8/2 = 4 in

The volume of the ball

$v=4/3 \pi r^3$

$v= 4/3*3.142*4^3\\\\v= 4/3*3.142*64\\\\v= 804.35/3\\\\v=268.12 in^3$

Step two:

we know that

rate= quantity/time

rate= 2.4 in per second

quantity= 268.12

time=?

time= quantity/rate

time= 268.12/2.5

time= 107.2 seconds

4 0

3 years ago

Dan can run 1000 meters in 5 minutes how many can he run in 2 minutes

Rudik [331]

Answer:

800 m

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers