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Genrish500 [490]
3 years ago
5

In the first 120 miles over 240 mile journey a truck driver maintained an average speed of 50 mph what was his average featuring

the next 120 miles if the average speed of the entire trip with 60 mph
Mathematics
2 answers:
Keith_Richards [23]3 years ago
3 0
The correct answer is 70 MPH because when 50 and 70 are added together and divided by 2, you get 60.
julsineya [31]3 years ago
3 0
The average speed over the entire trip was 60 mph, which must equal the distance traveled (240 miles) times the elapsed time.  Dividing  60 mph into 240 miles gives us the elapsed time:  (240 miles) / (60 mph) = 4 hours total.

Next:  determine the length of time required to drive the first 120 miles at 50 mph.  It is (120 miles) / (50 mph), or 2.4 hours.

Next, find the length of time required to drive the second 120 miles.  It is 4 hours less 2.4 hours, or 1.6 hours.

Lastly, find the average speed over which the second 120 miles were covered in 1.6 hours:

average speed (2nd 120 miles) = (120 miles) / (1.6 hours) = 75 mph.
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How to find the area of a square ABC D
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Answer:

The answer to your question is 13 u²

Step-by-step explanation:

We know that the small triangle is surrounded by right triangles so we can use the Pythagorean theorem to find the lengths  of the small triangle

                 AD² = 3² + 2²

Simplify

                 AD² = 9 + 4

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Find the area of the square

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6 0
4 years ago
The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity v_0 , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0
3 years ago
Worth 12 Points, i spent 24
rewona [7]

Answer:

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Step-by-step explanation:

The relevant rule of exponents is ...

  (a^b·c^d)^e = a^(be)·c^(de)

Then ...

  (m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)

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__

Since you want positive rational exponents, you can write this as ...

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6 0
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trasher [3.6K]

Answer:

A) Ms. Hynnes'

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Step-by-step explanation:

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